大家帮帮忙，我看了5分钟看不出这题什么意思，翻译的我蛋疼！！！！！！！！

tyzgmat

FOR A FINITE SEQUENCE OF NONZERO NUMBERS, THE NUMBER OF VARIATIONS IN SIGN IS DEFINED AS THE NUMBER OF PAIRS OF CONSECUTIVE TERM OF THE SEQUENCE FOR WHICH THE PRODUCT OF THE TWO CONSECUTIVE TERM IS NEGATIVE. WHAT IS THE NUMBER OF VARIATIONS IN SIGN FOR THE SEQUENCE 1，-3,2,5，-4，-6

mikiqmouse

对一列不为零的有限数集， THE NUMBER OF VARIATIONS IN SIGN 被定义为： 两个相邻的数字的乘积为负。 问你下列数哪些可以满足条件：
有：-3/2  5/-4 5/-6

shevit

是3不？楼主分析下句子成份翻译出来的，加油

tyzgmat

答案是三啊，可是怎么得出的！！！！！！！！！！！！！

欧阳小西

一楼分析份儿很正确啊  在不为零的一个序列里  那个东西被定义为：两个响铃的数的乘积为负。  那么有三对数，答案就是3啊！  the number of pairs啊。

MarsTOF

对一列不为零的有限数集， THE NUMBER OF VARIATIONS IN SIGN 被定义为： 两个相邻的数字的乘积为负。 问你下列数哪些可以满足条件：
有：-3/2  5/-4 5/-6

-- by 会员 mikiqmouse (2011/6/26 15:54:16)

MarsTOF

好吧 我看错了。。还有1。。话说1L的答案有问题啊。。

shevit

FOR A FINITE SEQUENCE OF NONZERO NUMBERS, THE NUMBER OF VARIATIONS IN SIGN IS DEFINED AS THE NUMBER OF PAIRS OF CONSECUTIVE TERM OF THE SEQUENCE FOR WHICH THE PRODUCT OF THE TWO CONSECUTIVE TERM IS NEGATIVE. WHAT IS THE NUMBER OF VARIATIONS IN SIGN FOR THE SEQUENCE 1，-3,2,5，-4，-6

-- by 会员 tyzgmat (2011/6/26 15:45:14)

FOR A FINITE SEQUENCE OF NONZERO NUMBERS, THE NUMBER OF VARIATIONS IN SIGN ISDEFINED AS THE NUMBER OF PAIRS OF CONSECUTIVE TERM OF THE SEQUENCE FOR WHICH THE PRODUCT OF THE TWO CONSECUTIVE TERM IS NEGATIVE. WHAT IS THE NUMBER OF VARIATIONS IN SIGN FOR THE SEQUENCE 1，-3,2,5，-4，-6
题目的意思就是说一个数的左右相邻的数的PRODUCT（乘积）是负数。
所以对这个数列来说，2左右分别为（-3，5）他们乘积是负的。5的左右是（2，-4）乘积为负，-4的左右（5，-6）成绩为负，所以就是2，5，-4这三个数满足要求，是THE NUMBER OF VARIATIONS IN SIGN

shevit

因为2的左右两个数（1，5）他们的PRODUCT为POSITIVE，不是NEGETIVE~

mythology

因为2的左右两个数（1，5）他们的PRODUCT为POSITIVE，不是NEGETIVE~

-- by 会员 shevit (2011/6/30 21:30:37)

2的左右是1,5？
没看懂，求解释