这道gap题，很纠结...那位NN能指点一下，帮我写一下思路的....

ainiAnnie · 发表于 2012-5-3 08:26:53

People who do not believe that others are smarter than them are confident in their own abilities. Hence,people who tend to outsmart others think of a difficult task as a showcase rather than a hurdle, since this is precisely how people who are confident in their own abilities regard such tasks.

The conclusion above follows logically if which one of the following is assumed?

(A)

eople who believe that others are smarter than them tend to outsmart others.

(B) Confidence in one’s own abilities gives one confidence to outsmart others.

(C)

eople who tend to outsmart others do not believe that others are smarter than them.

(D)

eople who are not hampered by difficult tasks tend to treat such tasks as opportunities to show off.

(E)

eople tend to outsmart those who they believe lack self-confidence.

哪位NN可以帮我写一下逻辑链和思维过程？？？非常感谢！！！！

maestri · 发表于 2012-5-3 08:48:40

这道题属于偷换了概念的。
把People who do not believe that others are smarter than them 与 people who tend to outsmart others这两类人等同起来，那么填补gap的描述一定是说这两类人其实是一类人，之后的结论就match了，即“比别人聪明的人”属于“不相信别人比自己聪明的人群”，因此选C

sdcar2010 · 发表于 2012-5-3 08:58:36

LS is right.

Yiayia's explanation is also to the point:

http://forum.chasedream.com/GMAT_CR/thread-498347-1-1.html?userid=688165

The key is to write down all the logical arguments presented in the passage, like what Yiayia did. Then the gap is obvious if you want to go from "

eople outsmart others" to "people showcase their abilities,", the main conclusion of the passage.

ainiAnnie · 发表于 2012-5-3 09:51:06

LS is right.

Yiayia's explanation is also to the point:

http://forum.chasedream.com/GMAT_CR/thread-498347-1-1.html?userid=688165

The key is to write down all the logical arguments presented in the passage, like what Yiayia did. Then the gap is obvious if you want to go from "

eople outsmart others" to "people showcase their abilities,", the main conclusion of the passage.

-- by 会员 sdcar2010 (2012/5/3 8:58:36)

thx~~~~~soooooooooooo much~~~~
Premise1:People（S） who do not believe that others are smarter than them are confident in their own abilities.Hence,conclusion：people（O） who tend to outsmart others think of a difficult task as a showcase rather than a hurdle,since primise2:this is precisely how people（C） who are confident in their own abilities regard such tasks.

S→O

C→O

when I first deal with this problem, I focus too much on “hence” and “since”, and I want to figure out the logic chain as always.

I got that:primise1+primise2→conclusion，so we need：S=C

How terrible！！I leave out many elements. I have no idea what I was thinking about at that time.

Now I figure it out:

People（S） who do not believe that others are smarter than them are confident in their own abilities. Hence,people（O） who tend to outsmart others think of a difficult task as a showcase rather than a hurdle, since this is precisely how people who are confident in their own abilities regard such tasks.

1.S→C
O→T，1结合2可以退出S→T，而我们需要O→T，所以必须有O=S

2.C→T

ainiAnnie · 发表于 2012-5-3 09:52:31

这道题属于偷换了概念的。
把People who do not believe that others are smarter than them 与 people who tend to outsmart others这两类人等同起来，那么填补gap的描述一定是说这两类人其实是一类人，之后的结论就match了，即“比别人聪明的人”属于“不相信别人比自己聪明的人群”，因此选C

-- by 会员 maestri (2012/5/3 8:48:40)

这位大侠，感觉你很快并且很轻松就找到了...怎么这么快...我纠结了好久呢，能写写具体的方法么？？谢谢！！！

maestri · 发表于 2012-5-3 10:27:10

我也只是刚开始做逻辑题而已，没有什么方法，只是单纯的根据题意推测、排除或者跟着感觉，几乎是当作阅读理解来做的。
我这种是最原始的做题模式，我也希望能够系统的梳理下思路，找到一套适合自己的做题方式。
大家一起进步吧。

ainiAnnie · 发表于 2012-5-3 10:29:10

我也只是刚开始做逻辑题而已，没有什么方法，只是单纯的根据题意推测、排除或者跟着感觉，几乎是当作阅读理解来做的。
我这种是最原始的做题模式，我也希望能够系统的梳理下思路，找到一套适合自己的做题方式。
大家一起进步吧。

-- by 会员 maestri (2012/5/3 10:27:10)

我以前也这样...题目读懂就容易做对，可是这道题的element太多啦！！！你怎么区分的出来的呀...我看看都混了...

maestri · 发表于 2012-5-3 10:55:28

这道题看懂了还是很好做的。

出现三种人群：
1：不相信别人比自己聪明的人------------自己以为聪明
2：比别人聪明的人---------------------事实上比别人聪明
3：对于能力自信的人------------------本题中可视为等同于第一类人

结论是：因为3有某种属性，所以2也具有某种属性。结论的问题在于：怎么能把3的属性放在2身上呢？

那么就需要建立来搭桥某种联系了。

翻译：不相信别人比自己聪明的人（人群1）对于自身能力很有自信（这句话建立了1和3的联系）。因此，那些比别人聪明的人（人群2：这里偷换了概念）将困难的任务当作展示舞台而非障碍（指出属性），因为那些对于能力自信的人（人群3）就是这样看待此类任务的（这里建立了1/3人群与属性的联系）。

下列哪个假设正确时，以上结论是有逻辑的？

答案：C）比别人聪明人的不相信别人比自己聪明-----将1和2连接起来的选项

ainiAnnie · 发表于 2012-5-3 11:38:14

这道题看懂了还是很好做的。

出现三种人群：
1：不相信别人比自己聪明的人------------自己以为聪明
2：比别人聪明的人---------------------事实上比别人聪明
3：对于能力自信的人------------------本题中可视为等同于第一类人

结论是：因为3有某种属性，所以2也具有某种属性。结论的问题在于：怎么能把3的属性放在2身上呢？

那么就需要建立来搭桥某种联系了。

翻译：不相信别人比自己聪明的人（人群1）对于自身能力很有自信（这句话建立了1和3的联系）。因此，那些比别人聪明的人（人群2：这里偷换了概念）将困难的任务当作展示舞台而非障碍（指出属性），因为那些对于能力自信的人（人群3）就是这样看待此类任务的（这里建立了1/3人群与属性的联系）。

下列哪个假设正确时，以上结论是有逻辑的？

答案：C）比别人聪明人的不相信别人比自己聪明-----将1和2连接起来的选项

-- by 会员 maestri (2012/5/3 10:55:28)

你好强大啊...你做题的时候完全在脑子里完成以上过程么....
我觉得我要标出来...
不然就混了...

单调唱 · 发表于 2012-5-3 16:13:33

我也只是刚开始做逻辑题而已，没有什么方法，只是单纯的根据题意推测、排除或者跟着感觉，几乎是当作阅读理解来做的。
我这种是最原始的做题模式，我也希望能够系统的梳理下思路，找到一套适合自己的做题方式。
大家一起进步吧。

-- by 会员 maestri (2012/5/3 10:27:10)

我以前也这样...题目读懂就容易做对，可是这道题的element太多啦！！！你怎么区分的出来的呀...我看看都混了...

-- by 会员 ainiAnnie (2012/5/3 10:29:10)

还是要有系统的逻辑做题方法，全靠感觉，题目读懂，然后自己天南地北想，这样一耗时间，二遇到难题，长题，就容易卡壳了~~

好好研读sdcar2010的逻辑入门贴，会大有所获的。

这道gap题，很纠结...那位NN能指点一下，帮我写一下思路的....

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