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已经刷到第五遍（还是第六遍？忘了），突然有点茅塞顿开的快乐。决定一点一点记录下来，欢迎讨论和分享！CD是个好平台！
一、Main Conclusion题
以前绕得好晕啊，各种方法和逻辑，但是感觉对我都不太适用，有点像去强制按那些大牛们的思路做题，但是明明知道这不是自己。。。
今天开始看CR OG12 正确的句子，发现亮点了！！！而且把OG里main conclusion的题全杀了一遍，全中！！！除了一个66题可能稍隐晦，别的都对了。
先说原理再给例子大家自己复习试试。
1、原理：MC题型我发现基本出题人是这样做的：事实1、事实2、事实3（复杂一点的会有事实3），而答案一般模式就是：把事实1、2代入事实3，可以得出的那句话。
发现没！！类似解代数方程式！！就是这样！！别不相信，我把OG题目粘给大家看。
2、举例：（题目来自OG12 CR）
101. For a trade embargo禁止出入港口 against a particular country to succeed, a high degree of both international accord协议，一致 and ability to prevent goods from entering or leaving that country must be sustained. A total blockade封锁 of Patria’s ports is necessary to an embargo, but such an action would be likely to cause international discord冲突 over the embargo.
The claims above, if true, most strongly support which of the following conclusions?
(D) Any trade embargo against Patria would be likely to fail at some time.
分析：P1给出了embargo俩条件。P2给出了P国不能同时具备着俩。C：P2≠P1。就是答案D！
102. Theater Critic: The play La Finestrina, now at Central Theater, was written in Italy in the eighteenth century. The director claims that this production is as similar to the original production as is possible in a modern theater . Although the actor who plays Harlequin the clown gives a performance very reminiscent暗示的，使人想起…的 of the twentieth-century American comedian Groucho Marx, Marx’s comic style was very much within the comic acting tradition that had begun in sixteenth-century Italy.
The considerations given best serve as part of an argument that
(D) the performance of the actor who plays Harlequin in La Finestrina does not serve as evidence against the director’s claim
分析：
P1 LF是18世纪意大利写的
P2 导演说LF尽量还原原著时代
P3 LF里的角色H让人想到20世纪的作品GM，但是GM是16世纪风
P2=P1，P3=1，所以！！P3=P2结论！ 就是答案D！
19. A computer equipped with signature-recognition software, which restricts access to a computer to those people whose signatures are on file , identifies a person's signature by analyzing not only the form of the signature but also such characteristics as pen pressure and signing speed. Even the most adept forgers cannot duplicate复制、完全一样的 all of the characteristics the program analyzes.
Which of the following can be logically concluded from the passage above?
(C) Nobody can gain access to a computer equipped with the software solely by virtue of skill at forging signatures.
分析：
背景 sr软件通过签名限制入口
P1 sr软件原理：不仅是form，还有pressure和speed
P2 最牛的都不能复制一样的签名
这题更简单，直接把P2代入P1就是结论，答案C！
43. Laws requiring the use of headlights during daylight hours can prevent automobile collisions . However, since daylight visibility is worse in countries farther from the equator, any such laws would obviously be more effective in preventing collisions in those countries. In fact. the only countries that actually have such laws are farther from the equator than is the continental United States.
Which of the following conclusions could be most properly drawn from the information given above?
(E) Daytime headlight laws would probably do less to prevent automobile collisions in the continental United States than they do in the countries that have the laws.
分析：
事实1：Hdattack collision→事实2：离得越远，laws越有效→事实3：比us离得远的国家有laws。
把事实1和事实2代入事实3，就是答案！
LZ在刷第一遍第二遍甚至第三遍的时候，43题和102题一直半知半解！现在终于清晰多了！你会发现，GMAC出题的思路大部分就是：先给一个普适性的原理或事实，再给一个个案的小例子并且告诉你它一些特点（通常跟前面的原理有关的，要相信CR题干没有废话！），然后Main Conclusion就是像代数题一样，把特定的x值代入y方程，y的结果就是答案！
这样解题一定不会偏！因为y方程里没有的，一定不是答案！！
--------------------------------------更新分割线，没想到下午马上就在weaken题型里继续找到了代数思维--------------------------------------------
（二）Weaken题型
其实作为处女座且是女生，weaken题我还是挺有自信的（自黑）。可是一直处于黑一题算一题，自己能想到的attack有答案就能做对，想不到的但是答案列出来了的就要费脑子。明显是缺乏科学逻辑思维凭经验的搞法。没办法月底就要考试了时间紧迫，处女座另外一大亮点个性要闪光了——做总结！
代数思维再一次救了时间段考期紧的我。废话不说！切入正题。
1、原理：
GMAC的weaken题型前辈们大多数牛人都总结了，最经典的当然是helr的6大分类：类比、统计、方案、相关因果、果因、因果。这个确实最早给了我很大启发！当时我就在考虑这些分类最终在逻辑链里如何去运用呢？还是线性代数！！
Y=ax+b
又在刷OG，渐渐发现：GMAC对CR weaken的出题思路—— 题干告诉你，此题的变量有x和y，结论是x变化就可以得出y变化。如何去weaken这个结论？
请大家脑补Y=ax+b方程式，你就会看到，如x的变化可以直接反应到y对应变化，有三个方面——x本身、a和b。
x自然不说，直接否定x和y的关系，太直白太露骨。但是要防止GMAC的变体形式题（后面我列的第一个例子）
a：代表了跟x相关。最简单的理解莫过于，题干的环境发生了变化，导致a1和a2不相等，所以x变化时，y不一定能得出！
b：代表了传中的第三者。最简单的理解（也是GMAC最爱出的类型），y结论的发生，可不可能是b造成的？
所以整个weaken题型就是在寻找a和b，因为不同于main conclusion的地方在于，weaken题型里一般结论是交代给你的。
那么，一定要记住：因为CR是无法在几句话里做到穷举的，所以一定有漏洞可以给你抓住！要有这个信心。
来几道OG题目给大家加深下理解：
104. Although the discount stores in Goreville’s central shopping district are expected to close within five years as a result of competition from a SpendLess discount department store that just opened, those locations will not stay vacant for long. In the five years since the opening of Colson’s, a non-discount department store, a new store has opened at the location of every store in the shopping district that closed because it could not compete with Colson’s.
Which of the following, if true, most seriously weakens the argument?
(B) Increasingly, the stores that have opened in the central shopping district since Colson’s opened have been discount stores .
分析：这题我做错过好几次，在CD上翻过好多帖子想弄明白，但还是晕！发现强大的代数思维再一次解决了我T^T
P1 S折扣店开张，导致G区的其他折扣店都关门，在未来五年。
C 这些关掉的门面并不会空很久
P2 一种non-discount的C店开了，new store已经在PK不赢C店而倒闭的门店上又开了起来
Y=vacant，X=开的新店。本题的X只有两种可能=discount store和non-discount store
P1告诉我们的是，当X=discount store时，Y成立。Y1=A×X1+B。
P2告诉我们的是，X已经又来了，但是不知道是不是discount！结果GMAC居然就得出了Y一定不成立！是不是很扯！
问题问什么情况下，Y会继续vacant？当然是新的X继续服从P1的方程时！也就是X2=X1的时候！没错只有答案B！
总结：一定要找准X和Y的变量到底是谁，然后就看它七十二变！
上面这题偏难，但是很激动我终于想明白了。来道经典的、更经常会考的、简单的例子：
114. Guidebook writer: I have visited hotels throughout the country and have noticed that in those built before 1930 the quality of the original carpentry work is generally superior to that in hotels built afterward. Clearly carpenters working on hotels before 1930 typically worked with more skill, care, and effort than carpenters who have worked on hotels built subsequently.
Which of the following, if true, most seriously weakens the guidebook writer’s argument?
(D) The better the quality of original carpentry in a building, the less likely that building is to fall into disuse and be demolishe
分析：这题是典型的a变量发生改变。
背景：all hotels visited（样本已充足，不要想weaken作者这一点）
P1 quality（1930前）＞quality（1930后）
C skill&effort（1930前）＞skill&effort（1930后）
方程式就变成了：skill&effort=a×quality+b
想weaken，x和y的关系就从a和b入手。
D选项：a不一样！a（1930前）≠a（1930后）——a是demolish（如果1930前的hotel是demolish了，那么x的影响因子a就不相等了！）
所以原方程式不成立。即skill&effort（1930前）不一定＞skill&effort（1930后）
再来一道b不一样的，这种从第三者找原因的题最常考，不过现在看来也最简单了。弄个稍微复杂点的，也就是x是由多个因素构成的：
111. The difficulty with the proposed high-speed train line is that a used plane can be bought for one-third the price of the train line, and the plane, which is just as fast, can fly anywhere. The train would be a fixed linear system, and we live in a world that is spreading out in all directions and in which consumers choose the freewheel systems (cars, buses, aircraft), which do not have fixed routes. Thus a sufficient market for the train will not exist.
Which of the following, if true, most severely weakens the argument presented above?
(C) Planes are not a free-wheel system because they can fly only between airports, which are less convenient for consumers than the high speed train’s stations would be.
P1 price：train=1/3的plane
P2 speed和范围 plane＞train
P3 行驶线路：train是固定的，但是cars、buses、plane都是freewheel
y=（speed+price+free wheel）×a +b
C 因为train的speed+price+free wheel都是最弱，所以train的y也最弱
这个找weaken就很容易了！只要（speed+price+free wheel）任意一个train不是最弱、或者train的b比他们大，train就有了胜出的优势！
答案C: b=convenient，且plane的free wheel和train一样弱！双响炮啊，所以y不成立！
数学万岁！！！T^T 我崇拜所有数学成绩好的娃，我也要努力。
接着刷，有体会了就分享！
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发表于 2014-4-10 11:46:08
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