标题: 求教og 13 problem solving 196 题 [打印本页] 作者: sissielizabeth 时间: 2012-8-31 23:56 标题: 求教og 13 problem solving 196 题 From the consecutive integers -10 to 10, inclusive, 20 integers are randomly chosen with repitions allowed.What is the least possible value of the product of the 20 integers? A (-10)^20 B (-10)^10 C 0 D -(10)^19 E -(10)^20 Answer: If -10 is chosen an odd number of times and 10 is chosen the remaining number of times (for example, choose -10 once and choose 10 nineteen times, or choose -10 three times and choose 10 seventeen times), then the product of the 20 chosen numbers will be -(10)^20.Note that -(10)^20 is less than -(10)^19,the only other negative value among the answer choices. the correct answer is E