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标题: GWD-8-Q21 [打印本页]
作者: 幸运E枪兵 时间: 2012-7-16 18:59
标题: GWD-8-Q21
Last year all refuse collected by Shelbyville cityservices was incinerated. Thisincineration generated a large quantity of residue ash. In order to reduce the amount of residue ashShelbyville generates this year to half of last year’s total, the city hasrevamped its collection program. Thisyear city services will separate for recycling enough refuse to reduce thenumber of truckloads of refuse to be incinerated to half of last year’snumber.
Which of the following is required for the revampedcollection program to achieve its aim?
A. This year, no materials that city services could separate for recyclingwill be incinerated.
B. Separating recyclable materials from materials to be incinerated will costShelbyville less than half what it cost last year to dispose of the residueash.
C. Refuse collected by city services will contain a larger proportion ofrecyclable materials this year than it did last year.
D. The refuse incinerated this year will generate no more residue ash pertruckload incinerated than did the refuse incinerated last year.
E. The total quantity of refuse collected by Shelbyville city services this yearwill be no greater than that collected last year.
作者: 幸运E枪兵 时间: 2012-7-17 11:57
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作者: 幸运E枪兵 时间: 2012-7-18 10:30
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作者: 幸运E枪兵 时间: 2012-7-19 15:35
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作者: 大飞哥 时间: 2012-7-19 16:17
题目看的好纠结!
作者: AvandarB 时间: 2012-7-19 16:37
number of truckloads of refuse (A) * amount of residual ash produced per truckload (B) = the amount of residual ash produced (C).
the question asks you to find a criteria to hold
1/2 A * B = 1/2 C
clearly, you have to hold B constant, thus you need to have refuse per truckload somehow constant. Only option D is suitable in this case.
当然,这只是一个所有的简化过程。。。
我是这么想的,不知道对不对
作者: Donts 时间: 2012-7-19 19:34
goal是减少灰烬ash,而不是减少refuse,E看上去很合理,但是你否定D选项看看,尽管refuse变少,但是燃烧它产生的ash更多不是仍然不能完成goal吗。
所以D比较符合
作者: sissi0305 时间: 2012-7-26 08:50
refuse减少到去年量的一半而不是今年的一半,跟今年总量多少没有关系
作者: lei06100610 时间: 2012-10-28 21:41
a也有道理啊,如果被回收的垃圾里还是有一部分需要焚烧,那也达不到减半的效果
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