标题: 求助几道GWD数学题！呼唤好心人 [打印本页] 作者: 苗苗心圃G 时间: 2012-5-22 23:15 标题: 求助几道GWD数学题！呼唤好心人 GWD4-Q1:这题我不明白题意。。。。 Of the fruit that arrives at a cannery, 20 percent by weight is rejected before processing.Of the fruit that is processed, 15 percent by weight is rejected before canning.Of the fruit that arrives at the cannery, what percent by weight is canned?
A.32% B.35% C.65% D.68%
E.70%
GWD4-Q4:这题我一开始选的A For a nonnegative integer n, if the remainder is 1 when 2n is divided by 3, then which of the following must be true?
I.n is greater than zero. II.3n = (-3)n III.√2nis an integer.
A.I only
B.II only C.I and II
D.I and III
E.II and III
Q13:这题我没领会啥意思呢。。。答案是C，我选的B Lists S and T consist of the same number of positive integers.Is the median of the integers in S greater than the average (arithmetic mean) of the integers in T? (1)The integers in S are consecutive even integers, and the integers in T are consecutive odd integers. (2)The sum of the integers in S is greater than the sum of the integers in T.
求好心人赐教啊！
GWD4-Q4:这题我一开始选的A For a nonnegative integer n, if the remainder is 1 when 2n is divided by 3, then which of the following must be true?
I.n is greater than zero. II.3n = (-3)n III.√2nis an integer.
A.I only
B.II only C.I and II
D.I and III
E.II and III
Q13:这题我没领会啥意思呢。。。答案是C，我选的B Lists S and T consist of the same number of positive integers.Is the median of the integers in S greater than the average (arithmetic mean) of the integers in T? (1)The integers in S are consecutive even integers, and the integers in T are consecutive odd integers. (2)The sum of the integers in S is greater than the sum of the integers in T.
求好心人赐教啊！ 作者: 苗苗心圃G 时间: 2012-5-22 23:16
呃。。。一不小心把二三题发了两遍。。。。作者: gina2012 时间: 2012-5-22 23:28
the first one is straightforward,
ask you from the original fruit coming in to what has been made in cans, what is the percentage of those in can divided by the original
(1-20%) times (1-15%) = 68%作者: gina2012 时间: 2012-5-22 23:30
the first one is straightforward,
ask you from the original fruit coming in to what has been made in cans, what is the percentage of those in can divided by the original
(1-20%) times (1-15%) = 68%作者: gina2012 时间: 2012-5-22 23:35
the second one
if the remainder is 1 when 2n is divided by 3,
this sentence means that n is either 0 or even times multiple of 2
so I and II作者: 苗苗心圃G 时间: 2012-5-23 23:53
谢谢！ 请问第三题咋解呢？作者: gina2012 时间: 2012-5-24 00:01
From 1, S={2,4,6} and T={1,3,5} or S={2,4,6} and T={3,5,7} Insufficient
From 2 S={1,2,10} and T={1,2,3} or S={1,5,6} and T={1,2,3} Insufficient
Combining both: Same number of positive integers. S consecutive even integers T consecutive odd integers Sum(s)>Sum(t) For this, t's starting point needs to be smaller than s's starting point So, AM of T < Median of S Sufficient.
Note: I am assuming here that "S and T consist of the same number of positive integers" means "S and T contain only positive integers and total number of integers is same". If we dont assume this, total number of integers (that includes negative numbers) in S and T becomes unknown, leading to E.
this one, I too view the question wrong, so I did a little search. It is simple.
I think GMAt is tricky because they delibrately put the quesion to confuse you.