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标题: GMAT 逻辑分析题 (3) [打印本页]

作者: sdcar2010    时间: 2010-11-10 06:32
标题: GMAT 逻辑分析题 (3)
People who do not believe that others are smarter than them are confident in their own abilities. Hence, people who tend to outsmart others think of a difficult task as a showcase rather than a hurdle, since this is precisely how people who are confident in their own abilities regard such tasks.

The conclusion above follows logically if which one of the following is assumed?

(A)  People who believe that others are smarter than them tend to outsmart others.

(B)  Confidence in one’s own abilities gives one confidence to outsmart others.

(C)  People who tend to outsmart others do not believe that others are smarter than them.

(D)  People who are not hampered by difficult tasks tend to treat such tasks as opportunities to show off.

(E)  People tend to outsmart those who they believe lack self-confidence.

作者: eshopaholic    时间: 2010-11-10 09:57
the assumption must brige the two concepts "people who tend to outsmart others" and "people who are confident in their own abilities"

I choose C
作者: sdcar2010    时间: 2010-11-11 07:10
Good answer and correct analysis.  
作者: gelukkig    时间: 2011-10-3 22:09
Why not B? B also provide a bridge
作者: sdcar2010    时间: 2011-10-3 22:14
Why not B? B also provide a bridge
-- by 会员 gelukkig (2011/10/3 22:09:02)



Please show your thinking process by pointing out the gap you mentioned and the way through which choice B bridges the gap. Then see if by filling the gap with B would ENABLE the main conclusion of the argument to be drawn from the premises given. If so, B is the correct answer choice. If not, B is not the sufficient assumption we need as the correct answer.
作者: 引夕    时间: 2011-10-17 22:36
一开始也选的B= =....然后再回去看发现问题了……
B说的是onfidence in one’s own abilities gives one confidence to outsmart others. 连接了 confidence in one's own abilities和 confidence to outsmart others. 其实还是和句意中的要求的连接有微妙的区别…………
逻辑好难啊啊抱头
作者: 月照琳琅    时间: 2011-11-6 17:52
gap   C
作者: lxsabrina    时间: 2012-3-14 11:42
NN好厉害
作者: 浅吟天    时间: 2012-3-18 14:44
不好意思,还是没懂c对在哪里?
结论“ people who tend to outsmart others think of a difficult task as a showcase rather than a hurdle” 和我们补的这个GAP有什么关系
作者: sdcar2010    时间: 2012-3-18 21:12
This is a sufficient assumption question because the word IF in the question stem.

As such, you need to plug in the answer choices and see which one would make the argument complete.

If you pay attention to the conclusion, you would notice that "people who tend to outsmart others", which is a trigger, is not mentioned anywhere else in the passage. Thus, we need that trigger in the correct answer choice.

Only C) fits the bill and when you plug in C), the whole argument works!
作者: 浅吟天    时间: 2012-3-20 19:09
嗯我终于懂了~我把outsmart 和smarter等同在一起了,所以没看出gap来
ps 姐姐上一张头像好看 好看的~~
作者: yiayia    时间: 2012-3-21 11:12
哈哈,这题跟我之前做的一题好像,完全可以用数学的集合概念来解。

Premise 1eople who do not believe that others are smarter than them(集合小)-----> People confident in their own abilities(集合大)

Premise 2eople confident in their own abilities(集合大)---->eople showcase(集合大大)

Conclusioneople outsmart(新集合)----->people showcase(集合大大)

还差一个premise 3:People outsmart(集合小小)--->people do not believe that others are smarter than them(集合小)

连起来就是people who outsmart are people who do not believe that others are smarter than them.
people who do not believe that others are smarter than them are people who are confident in their own abilities.
people who are confident in their own abilities are people who like to showcase.Nice "trigger"~~~

people who tend to outsmart others是最小的概念。
因为People who do not believe that others are smarter than them are confident in their own abilities. 不等于 people who are confident are people do not believe that others are smarter.
A--->B and B   X---->A 说明A在B的集合之内。
作者: jiajiajudy    时间: 2012-7-30 02:41
好搞的。。。 其实是要对outsmart 做出补充说明
作者: fantasy198    时间: 2012-8-1 09:34
B要仔细读。B的细微差别在于如果取非,没有confidence也可能outsmart,也可能不,没有逻辑链。
作者: babybearmm    时间: 2012-8-1 16:40
这题有意思啊~做个笔记就比较容易了:

Premise 1: NOT beli oth sm ====> conf
Premise 2: conf ====> think dif as show


Conclusion: outsm ====> think dif as show


所以assumption肯定是:
outsm ====> NOT beli oth sm加上这一条,就可以串成conclusion了
选(C)
作者: zhaixuting    时间: 2013-5-19 00:18
babybearmm 发表于 2012-8-1 16:40
这题有意思啊~做个笔记就比较容易了:Premise 1: NOT beli oth sm ====> confPremise 2: conf ====> think  ...

非常清晰!感谢
作者: livebelieve    时间: 2016-11-4 21:21
相关推理题,主要要知道e confident in their own abilities=hink of a difficult task as a showcase rather than a hurdle




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