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标题: prep 数学 请教 [打印本页]

作者: hehejack    时间: 2010-7-26 16:24
标题: prep 数学 请教
请教各位nn一道prep数学题;
Each  employee on a certain task is either a mananger or a director, what percentage of employee on the task are managers?
(1) Tha average (arithmetic mean ) salary of the managers on the task is $5000 less than the average of all employee of the task
(2) Tha average (arithmetic mean ) salary of the directors on the task is $15000 greater than the average of all employee of the task

答案是C,两个一起就是sufficient,单独一个不是

百思不解,average和人数的关系是什么?还有,each manager或者each director的工资相等吗?
作者: maggie520    时间: 2010-7-26 16:28
employee on a certain task is either a mananger or a director 这句话告诉你这个员工不是manager就是director,因此 要percentage的话就需要2种职位的工资. 所以光知道1)或者2)是不够的。
director= 15000+avg
manager=avg-5000
you want to know manager/(manager+director) x100%
作者: wenjie87    时间: 2010-7-26 16:36
设总人数为n,  manager占总人数的比例为x,  average salary of all employee为k
那么,两个条件合起来就可以得到表达式   n*x(k-5000)+n*(1-x)(k+15000)=n*k
化简约分出来就可得到 x=3/4
作者: hehejack    时间: 2010-7-26 20:04
懂了,谢谢啊。但是还是有个隐含的前提是每个M或者每个D的salary是相同的。




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