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标题: 求助PREP一题~~~~~~~~~~~~~~~~~~~~~ [打印本页]

作者: rx_11    时间: 2010-7-16 14:06
标题: 求助PREP一题~~~~~~~~~~~~~~~~~~~~~
if x and y are positive integers, is x an even integer?
(1)   x(y+5) is an even integer.
(2)   6y^2+41y+25 is an even integer
答案是E。。不解···求解答~~~
作者: youngerlee    时间: 2010-7-16 14:18
with following steps, I get an E answer.....

if x and y are positive integers, is x an even integer?
(1)   x(y+5)=even
(2)   6y^2+41y+25=even

[1]x(y+5)=even

when  y is even,   y+5 is an odd, then x should be even.
then  y is odd,  y+5 is even,  we have no idea about x in this case.

insufficient.


[2]6y^2+41y+25=even

25 odd, so 6y^2+41y should be odd AND SHOULD NOT BE 0

6y^2+41y should be odd means y[6y+41]should be odd

so y and [6y+41] should be all odds

when y even,  6y+41 odd  y[6y+41] even
when y odd, 6y+41 odd   y[6y+41] odd

then, y must be odd


take 'y=odd' into factor [1]
when y odd,  x have no idea

that's the answer

insufficient
作者: rx_11    时间: 2010-7-16 14:23
我也很想说:哪尼!!!!!

NN快来啊··
作者: youngerlee    时间: 2010-7-16 14:27
我也很想说:哪尼!!!!!

NN快来啊··
-- by 会员 rx_11 (2010/7/16 14:23:54)



soli, 刚才做错一步,现在做出来确实是E了
作者: rx_11    时间: 2010-7-16 14:28
我也很想说:哪尼!!!!!

NN快来啊··
-- by 会员 rx_11 (2010/7/16 14:23:54)




soli, 刚才做错一步,现在做出来确实是E了
-- by 会员 youngerlee (2010/7/16 14:27:39)



why??
作者: youngerlee    时间: 2010-7-16 14:35
我也很想说:哪尼!!!!!

NN快来啊··
-- by 会员 rx_11 (2010/7/16 14:23:54)





soli, 刚才做错一步,现在做出来确实是E了
-- by 会员 youngerlee (2010/7/16 14:27:39)




why??
-- by 会员 rx_11 (2010/7/16 14:28:42)



见2楼
作者: wenjie87    时间: 2010-7-16 14:36
(1)X(Y+5)偶
当Y为奇数时,Y+5为偶数,所以无论X是奇还是偶,算式都为偶
(2)6y^2+41y+25 is an even integer
  6Y^2为偶
  25为奇
   6Y^2+25为奇数,只有41Y为奇数时,等式才能是偶数
所以Y为奇数
综上,选E
作者: 毛毛carina    时间: 2010-7-16 14:38
条件二是可以推出y是奇数没有错

但把y为继续代入条件一,即y+5为偶数时,x不管是奇是偶,结果都是满足x(y+5)为偶数的,所以两个条件加起来还是insufficient
作者: rx_11    时间: 2010-7-16 14:40
...
understand~
thank you~




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