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标题: 十万火急！求助关于数学的均值问题! [打印本页]

作者: amyllei 时间: 2010-3-28 11:04
标题: 十万火急！求助关于数学的均值问题!
A certain city with a population of 132,000 is to be divided into 11 voting districuts, and no district is to have a population that is more than 10% greater than the population of any other district. What’s the Minimum possible population that the least populated distirct could be?

A.10,700

B.10,800

C.10,900

D.11,000

E.11,100

我的思路：假设最大的为X,最小的为Y, 据题意应有：
X-Y<=0.1Y, 则
Y>=1.1X

可为什么就能得出11,000的答案呢？难道就是为了取整？这也太牵强了吧？

紧急求助！多谢!

作者: Tess90 时间: 2010-10-21 23:55
假设最大的有10个，且都相等，是最小的1.1倍
这是最极端的情况，为了保证最小的是最小值。
那么（1.1*10+1）x=132000.
得到x=1100
貌似已经对不住这个十万火急了。。~

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