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标题: prep两道数学题~~不解啊。。。求助 [打印本页]

作者: dolorez    时间: 2009-12-6 22:38
标题: prep两道数学题~~不解啊。。。求助

1.      In the fraction x/y, where x and y are positive integers, what is the value of y?

The least common denominator of x/y and 1/3 is 6.

X=1.

2.    For manufacturer M, the cost of producing X units of its product per month is given by c=kx+t, where c is in dollars and k and t are constants. Last month if manufacturer M produced 1000 units of its product and sold all the units for k+60 dollars each, what was manufacturer M’s gross profit on the 1000 units?

Last month, Manufacturer M’s revenue from the sale of the 1000 units was 150,000

Manufacturer M’s cost of producing 500 units in a month is 45,000 less than its cost of producing 1000 units in a month.








作者: dolorez    时间: 2009-12-8 21:54
标题: 帮帮忙啊,谢谢!!
help help~~~
作者: celineyo    时间: 2009-12-8 21:58
正确答案是什么呀?
作者: dolorez    时间: 2009-12-8 22:24
标题: 答案是e
两个答案都是E
作者: sprtng    时间: 2009-12-8 22:33
1. 是E么, 如果x是1, 那y可能是2  或者 6...
2. 应该也是E吧, 只能求出K是90来, c跟t都是未知。。。
作者: dolorez    时间: 2009-12-8 22:43
标题:
第二题1的条件可以算出k,然后2的条件代入C方程不也可以求出那两个定量么
作者: dolorez    时间: 2009-12-8 22:50
标题: 我的解法
就是K=90,然后2的条件代入式45000=90乘以500+t,不就可以算出T吗
作者: sprtng    时间: 2009-12-9 00:56
2.    For manufacturer M, the cost of producing X units of its product per month is given by c=kx+t, where c is in dollars and k and t are constants. Last month if manufacturer M produced 1000 units of its product and sold all the units for k+60 dollars each, what was manufacturer M’s gross profit on the 1000 units?

Last month, Manufacturer M’s revenue from the sale of the 1000 units was 150,000

Manufacturer M’s cost of producing 500 units in a month is 45,000 less than its cost of producing 1000 units in a month.


第二题我列出来的式子是:
1. 1000(k+60) = 150000
2. 500*k - t +45000 = 1000k - t

t被cancel掉啦。。。还是求不出t到底是多少来, 所以 总的cost还是未知
作者: eric603    时间: 2009-12-9 05:50
一楼正解 两个都是e

1) Y=2 OR Y=6  => E

2) 条件1,2 其实都只能单独求出k=90, t未知,=》E




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