GWD1--Q29
June25,1982,fell on a Friday. On which day of the week did June 25,1987,fall?(Note:1984 was a leap year)
A.Sunday
B.Monday
C.Tuesday
D.Wednesday
E.Thursday
答案是选D,可是我觉得是选E
GWD12--Q11
THe product of the units digit,the tens digit,and the hundreds digit of the positive integer m is 96.What is hte units digit of m?
(1)m is odd
(2)The hundreds digit of m is 8
答案是A
Q16
If m,p and t are posotive integers and m<p<t, is the product mpt an even integer?
(1)t-p=p-m
(2)t-m=16
答案是选E,可是我认为是选A
Q30
M=(-6,-5,-4,-3,-2)
T=(-2,-1,0,1,2,3)
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above,what is the posibility that the product of the two integers will be negative?
A.0
B1/3
C.2/5
D1/2
E3/5
我认为答案是选 E,可是答案是选D
请问哪位大牛可以帮忙解答,谢啦
GWD1--Q29
June25,1982,fell on a Friday. On which day of the week did June 25,1987,fall?(Note:1984 was a leap year)
解:从1982-1987,共五年,合计365 X 4 + 366 (1984是闰年)=1826天
1826天/7天=260个星期零6天, 所以就是星期五再往后数六天,星期四.
GWD12--Q11
THe product of the units digit,the tens digit,and the hundreds digit of the positive integer m is 96.What is hte units digit of m? (1)m is odd; (2)The hundreds digit of m is 8
解:设M的百位,十位及个位分别为A,B,C (隐藏条件A,B,C小于等于9,且A,B,C不等于0)
则M=100A+10B+C, ABC=96.
条件(1),M为奇数,所以推出C亦为奇数. 因为能被96整除的奇数有1,3; C不能为1,如果C=1,则AB=96是不可能的.所以C=3.充分.
条件(2),百位数A=8, BC=12,可以是C=3,4,2,6; 不充分.
Q16
If m,p and t are posotive integers and m<p<t, is the product mpt an even integer?
(1)t-p=p-m
(2)t-m=16
解:
条件(1)推出T+M=2P, 即T+M是偶数(T和M可以同为奇,也可以同为偶),但P可以是偶数也可以是奇数,三数相乘,不能定奇偶;不充分;
条件(2),T和M可同为奇,同为偶,但P不一定是奇还是偶,不充分.
所以E.
我是这么认为的哦,不知对不对。。
一 二 三 四 五 六 日
6.25 26 27
28 29 30 1
一周是从1982年的6.25Fri到下一周的7.1Thur,当260个周过去以后,得从周五开始数6天,所以将是下周的Wed
Q30
M=(-6,-5,-4,-3,-2)
T=(-2,-1,0,1,2,3)
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above,what is the posibility that the product of the two integers will be negative?
A.0; B1/3; C.2/5; D1/2; E3/5
解: M中全为负值,所以要使MT为负,须在T中选取非负值,只有1,2,3可选, 所以 (C51C31)/(C51C61)=1/2,D. 留意, 0不是负数也不是正数.
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