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标题: 求助 GWD-18-Q15 [打印本页]

作者: zyhyxm 时间: 2008-8-18 12:31
标题: 求助 GWD-18-Q15

Fact: Asthma, a bronchial condition, is much less common ailment than hay fever, an allergic inflammation of the nasal passages.

Fact: Over 95 percent of people who have asthma also suffer from hay fever.

If the information given as facts above is true, which of the following must also be true?

A. Hay fever is a prerequisite for the development of asthma.

B. Asthma is a prerequisite for the development of hay fever.

C. Those who have neither hay fever nor asthma comprise less than 5 percent of the total population.

D. The number of people who have both of these ailments is greater than the number of people who have only one of them.

E. The percentage of people suffering from hay fever who also have asthma is lower than 95 percent

为什么选E？？

作者: dingshuaijun 时间: 2008-8-18 19:51

我也搞不懂，ABD一定错。我比较偏向于C。假设有100个人，如第2个fact说的，有超过95个人这2种病都有，那么还要设想有些是有其中一种的，那么不患病的自然就要少于5个人了。。。

不明。。。。

作者: dianecarton 时间: 2008-8-18 20:47

Asthma 比hay fever少见很多

超过95%的asthma 患者同时有hay fever,

E hay fever患者同时还有asthma的低于95%

作者: bubu_rachel 时间: 2008-11-3 11:07

我觉得应该是应该得那个hay fever比Asthma common，所以得hay fever的人比较多。如果画一下那个那个圆的图，就知道那个hay fever的圆比较大，那相交的面积占asthma的比较大，那自然占fever的就比较小。其实就是分母越大，结果越小的道理！～我是这样理解的，不知道对不对。。。

作者: 热带鱼 时间: 2008-12-20 22:35
设换A的有X,患有B的有Y，且Ｘ＜Ｙ
患有ＡＢ的有　９５％Ｘ< 95%Y

作者: Mayanist 时间: 2009-3-17 03:44

E -- 同时患两种病的人少于95%

可以用条件概率不严格描述：

因为asthma远少于hay fever, 也就是P(asthma)远小于1，例如20%，P(hay fever | asthma) > 95%

P(hay fever and asthma) = P(asthma) * P(hay fever | asthma) = 20%*95%

作者: Mayanist 时间: 2009-3-17 03:49

GWD18-15變形

Fact:
The percentage of people suffering from hay fever, an allergic inflammation of the nasal passages, who also have asthma, a bronchial condition, is lower than 95 percent.

Fact: Over 95 percent of people who have asthma also suffer from hay fever.

If the information given as facts above is true, which of the following must also be true?

A. Hay fever is a prerequisite for the development of asthma.

B. Asthma is a prerequisite for the development of hay fever.

C. Those who have neither hay fever nor asthma comprise less than 5 percent of the total population.

D. The number of people who have both of these ailments is greater than the number of people who have only one of them.

E. Asthma is much less common ailment than hay fever.

OA: E

Fact1: P(hay fever and asthma) <95%

Fact2: P(hay fever | asthma) > 95%

à P(asthma) << 95 %

作者: dustyrick 时间: 2009-3-17 11:42
X->

(Asthma)
Y->

(Fever)

X*Y/X > 95% ---> Y > 95%

Y*X/Y = X = P(Fever & Asthma)/ P(Fever)

cuz Y > 95% and Y > X ---> X < 95%
hence suffering from hay fever who also have asthma < 95%

作者: hairicanye 时间: 2009-3-21 15:19

这是一道包含数学公式的题：

Pa<h；，且Pa中同时有两种的的/Pa为95%，那么Ph中同时有两种的/Ph<95%

大家也可以用维恩图来考虑，更直观，不过恐怕在考场上...呵呵

作者: elaine1031 时间: 2009-7-20 16:53
up

作者: Simonyo 时间: 2009-8-4 21:34
up

作者: jesmine 时间: 2010-9-19 16:50
上传了副图一遍表达此关系

作者: robinwayne 时间: 2010-12-11 16:31
jesmine 还真是过细哈。

作者: Jennyqu 时间: 2010-12-17 01:40
图给力！UP!!XIEXIE~

作者: sdcar2010 时间: 2010-12-17 12:17
This is a basic math question and an inference question, which is equal to a Must Be True type question.

作者: 鱼筱洛 时间: 2010-12-17 23:59
jesmine很给力啊！！！

作者: gqiulu 时间: 2011-5-14 18:49
补充一个问题，题目里是Over 95%，而且并没有给出具体Asthma比fever要Less common多少，
如果接近100%的asthma患者也有fever，而fever只比asthma要common一点，这个must be true是不是就不一定成立了呢

作者: 396963484 时间: 2012-9-14 17:28
我也是这么想的。。。

作者: cannotliu 时间: 2012-9-15 07:32
画韦伯图，很好看

作者: Jianke311 时间: 2012-12-4 12:07
我也感觉这题E不正确,只说了A&H/A>95% ,那可以是97% ,或者是98%,那相应的就不一定是比95%小了，代数法则里面关于不等式的定理，若 1/x > y，且z > x，则1/z < y 吗？答案是不一定哦！！

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