If S in the infinite sequence S1=9, S2=99, S3=999,…, Sk=10k-1,…, is every term in S divisible by the prime number P?
1 P is greater than 2
2 at least one term in S is divisible by P.
The weights of four packages are 1, 3, 5 and 7 pounds, respectively. Which of the following CANNOT be the total weight, in pounds, of any combination of the packages?
9, 10, 12, 13, 14
If n is a positive integer and r is the remainder when (n-1)(n+1) is divided by 24, what is the value of r?
(1), n is not divisible by 2; (2), n is not divisible by 3
1,选E,e.x.可能是3,也可能是11.
2,14不可能,你怎么也加不出14来。
3,选E,e.x.:n=5时,r=12;n=7时,r=0.
3.
(1) n = 2k+1, (n-1)(n+1) = 2k(2k+2)= 4k(k+1) is divisible by 8
(2) n= 3k+1 or 3k+2, (n-1)(n+1) = 3k*(3k+2) or (3k+1)(3k+3), both are divisible by 3
If we combine (1) and (2), then n is surely divisible by 24. Thus the remainder r is always 0.
The answer should be (C)
err……我以为是被24除的余数……我的阅读能力…………
欢迎光临 ChaseDream (https://forum.chasedream.com/) | Powered by Discuz! X3.3 |