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标题: 记一道诡异的gaming [打印本页]

作者: flyshade_xie 时间: 2007-12-25 17:55
标题: 记一道诡异的gaming
Question
13-18



On an undeveloped street, a developer will simultaneously build four houses on
one side, numbered consecutively 1, 3, 5, and 7, and four houses on the
opposite side, numbered consecutively 2, 4, 6, and 8. Houses 2, 4, 6, and 8
will face houses 1, 3, 5, and 7, respectively. Each house will be exactly one
of three styles-ranch, split-level or Tudor-according to the following
conditions:



    　　Adjacent houses are of different styles.



    　　No split-level house faces another split-level house.

    　

    　　Every ranch house has at least one Tudor house
adjacent to it



    　　House 3 is a ranch house.



    　　House 6 is a split-level house.



15.
If house 4 is a Tudor house, then it could be true that house



    　　(A) 1 is a Tudor house

    　　(B) 2 is a Tudor house

    　　(C) 5 is a Tudor house

    　　(D) 7 is a Tudor house

    　　(E) 8 is a Tudor house





这是laws4u.net里下载的一套组题里的一道，答案说应该是A，但是我怎么觉得ACE都可以成立呢？C更加是个must be true的选项，这是怎么回事？？？

作者: 况天佑 时间: 2007-12-26 23:11
不是真题吧？

作者: cbb2 时间: 2007-12-27 04:34

Accrding to the rules:

S6 means 5 is not S, so 5 must have to be T, and then 7 can not be R or T, i.e. 7 is S. Hence,considering the rules, 8 is not S or R, and it has to be T.

If 4 is T, then 2 must not be T too, so it could be S or R. if 2 is S, then 1 is T, and if 2 is R, then 1 must be T.

so for the answers, E must be true, D must be wrong, C must be true, and B is wrong, only A could be true. So the answer is A.

The question is asking "could be true",not must be true. Therefore, you only got one choice, A.

作者: ivy3997 时间: 2007-12-30 18:43

why 7 cannot be R, I think it could be

在网上搜索了你这道题，是这个答案印错了

If house 4 is a Tudor house, then it could be true that house

　　(A) 1 is a Tudor house
　　(B) 2 is a Tudor house
　　(C) 5 is a ranch house
　　(D) 7 is a Tudor house
　　(E) 8 is a ranch house

[此贴子已经被作者于2007-12-30 18:54:05编辑过]

作者: cbb2 时间: 2007-12-31 00:28

关于'why 7 cannot be R, I think it could be'. 楼上说的对.我都忘了自己怎么得出的结论

但是重新分析了一下,针对问题一,3是R,5 是T,4是T,6是S,8不能是R或S,是T.7是R或S,不能是T.1可能是T或S,2是R或S.

(A) 1 is a Tudor house
　　(B) 2 is a Tudor house
　　(C) 5 is a Tudor house
　　(D) 7 is a Tudor house
　　(E) 8 is a Tudor house
所以,B and D can not be true. C and E must be true. ONLY A could be true.

对于楼上找到的答案;

只有A could be true, B C D E all can not be true

作者: taoransk 时间: 2010-10-1 18:33
If house 4 is a Tudor house, then it could be true that house

　　(A) 1 is a Tudor house
　　(B) 2 is a Tudor house
　　(C) 5 is a ranch house
　　(D) 7 is a Tudor house
　　(E) 8 is a ranch house

这个应该是标准的题目
LSAT里应该不存在must be true 和could be true 分开的情况, 因为must也是could 的一种, must 是100%, could是1-100%, cannot是0%.
所以不会出现两个100一个1-100然后问哪个大于0的情况.....
所以,只能说一楼写错了或者你书印错了......
貌似我在有一个网站作题就是人家写的时候错了结果我折腾了俩小时...

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