S is a set of points in the plane. How many distinct triangles can be drawn that have three of the points in S as vertices?
(1) The number of distinct points in S is 5.
(2) No three of the points in S are collinear.
Should the answer be (C)?
Any three points, if not collinear and not overlapped, should be able to decide a distinct triangle.
And a triangle requires three verticle points to be non collinear and, obviously, not occupying the same spot.
谢谢,上一题的答案是c,再帮我看看下面这道题
In the decimal representation of x, where 0 < x < 1, is the tenths digit of x nonzero?
(1) 16x is an integer.
(2) 8x is an integer.
Since 8x is an integer and x>0 ---> 8x>=1--->x>=0.125, --> tenths digit of x must be nonzero
16x>=1 --> x>= 0.0625 only
So the answer should be (B)
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