标题: LSAT-12-1-12 [打印本页] 作者: snow_mountain 时间: 2003-11-29 23:23 标题: LSAT-12-1-12 12. In the Centerville Botanical Gardens, all tulip trees are older than any maples. A majority, but not all, of the garden's sycamores are older than any of its maples. All the garden's maples are older than any of its dogwoods. If the statements above are true, which one of the following must also be true of trees in the Centerville Botanical Gardens? (A) Some dogwoods are as old as the youngest tulip trees. (B) Some dogwoods are as old as the youngest sycamores. (C) Some sycamores are not as old as the oldest dogwoods. (D) Some tulip trees are not as old as the oldest sycamores. (E) Some sycamores are not as old as the youngest tulip trees.
答案是E。 没想明白。 照我的想法 Some sycamores are as old as the youngest tulip trees. 也是成立的呀。
[此贴子已经被作者于2003-11-29 23:23:51编辑过]
作者: Snazzy 时间: 2003-11-30 11:40
hi, it seems for me there is some information missing or the description may be incorrect. according to the passage, i got the following fomula: Tulip>Maple>Dogwoods. since most of sycamores, not all, r older than maples, and of course, some of them r younger or as young as maples. thus, answer E is wrong. on the contrary, i think B is the right answer.
What do u think? 作者: snow_mountain 时间: 2003-11-30 12:09
i copy and paste the question from ELSAT. so who can check the orignial question and answer for me?
by the way, think B may be correct, but not must be so. your formula is correct. since some r are older than any maple. but not all of them.
the formula can also be Tulip>some sycamores> Maple>Dogwoods and Tulip> Maple>other sycamores>Dogwoods
in such case, B is wrong.
what do u think?
作者: cranberry 时间: 2003-11-30 15:11
e 是正确的,maplesmaples,so there must be some sy which are younger than some maples,and all the maples are younger than any tulip,so there must be some sy younger than any tulip作者: snow_mountain 时间: 2003-11-30 17:04 标题: LSAT-12-1-12 明白了。谢谢。
