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标题: 接着发问题吧! [打印本页]

作者: Drakedirect    时间: 2007-8-24 02:45
标题: 接着发问题吧!
在牛牛们的帮助下,今天模考数学终于有点进步了,第一次得了50分,大家见笑了,呵呵!
不过还是有些疑问。GMATPre上面的,多谢大家帮忙!

1. The points A, B, C, and D are on a number line, not necessarily in that order. If the distance between A and B is 18 and the distance between C and D is 8, what is the distance between B and D?
(1) The distance between C and A is the same as the distance between C and B
(2) A is to the left of D on the number line

Key:E
我选了A,估计是落掉了一些情况,请赐教!

2. If Z^n =1, what is the value of z?
(1) n is a nonzero integer
(2) z>0
key: C 我选了A, 感觉即便是Z<0,如果要Z^n =1,z也只能等于1吧?还能等于别的??不解

3. if x>y^2>z^4, which of the following statements could be true?
I.  x>y>z
II. z>y>x
III. x>z>y
A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III
key: E
做这种题我通常是带入一些数,但是经常会漏掉一些情况,所以这种题对我很头疼。我选了B不知道大家又没有什么好的办法来做这种题?谢了!

3. Henry purchased 3 items  during a sale. He received a 20 percent discount off the regular price of the most expensive item and a 10 percent discount off the regular price of each of the other 2 items. Was the total amount of the 3 discounts greater than 15 percent of the sum of the regular prices of the 3 items?
(1) the regular price of the most expensive item was $50, and the regualr price of the next most expensive item was $20.
(2) the regular price of the least expensive item was $15
key: A
我的方程式:(20%*A+10%*B+10%*c)/(a+b+c),看了答案,突然想起来可以用$20来代替c,接出来的值好像比15%大,可是问题是分子分母都还有C,怎么确定最后的值比这个大还是小呢?



作者: yedeanboy    时间: 2007-8-24 02:55
1. The points A, B, C, and D are on a number line, not necessarily in
that order. If the distance between A and B is 18 and the distance
between C and D is 8, what is the distance between B and D?
(1) The distance between C and A is the same as the distance between C and B
(2) A is to the left of D on the number line

Key:E
(1)只能说明C是A和B的中点(假设A和B不能是同一点),并且C到两者的距离各为9。那么D可以在C左边或者右边,距离C为8。无法确定BD的距离
(2)不能退出任何有用的结论
(1)和(2)结合也无法推出任何结论,因为CD=8而CA=9,所以只要A在C的左侧,都满足A在D的左侧,这时D可以在C左侧或者右侧,无法确定BD

不知道说清楚没有?

作者: yedeanboy    时间: 2007-8-24 02:58
2. If Z^n =1, what is the value of z?
(1) n is a nonzero integer
(2) z>0
key: C

(1)无法推出z的值,因为当n为偶数时,z可以等于1或者-1
(2)z大于0单独自然也无法推出z的值
两者合并得到,z>0 并且z=1或者-1,所以z必然等于1

作者: yedeanboy    时间: 2007-8-24 03:01
3. if x>y^2>z^4, which of the following statements could be true?
I.  x>y>z
II. z>y>x
III. x>z>y
A. I only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III
key: E

一般分析y和z大于1或者小于1大于0的情况,因为平方或者4次方会放大大于1的数而减小小于1的数
这类题确实很麻烦,很容易错。

作者: yedeanboy    时间: 2007-8-24 03:07
3. Henry purchased 3 items  during a sale. He received a 20 percent
discount off the regular price of the most expensive item and a 10
percent discount off the regular price of each of the other 2 items.
Was the total amount of the 3 discounts greater than 15 percent of the
sum of the regular prices of the 3 items?
(1) the regular price of the most expensive item was $50, and the regualr price of the next most expensive item was $20.
(2) the regular price of the least expensive item was $15
key: A

题目问是否能确定总折扣大于15%,所以你只要确定折扣最小时能大于15%就可以了
(1)折扣最小时发生在最便宜的物品价格也是20时。总折扣为(20%*50+10%*40)/90=14/90=15.6%
所以(1)可以

(2)仅仅给出最便宜的物品的价格无法确定总折扣。可以举极端的例子。比如3个商品价格一样,则小于15%,最贵的那个商品价格为1000,则必然大于15%

所以选A

作者: Drakedirect    时间: 2007-8-24 03:12
yedeanboy,第一题的思路果然清晰,我做的时候画了半天,费了好多时间,还是做错了,按照你讲很容易就选E了。每次看到这种题目,脑子就乱了,不知道从哪里下手!
作者: Drakedirect    时间: 2007-8-24 03:12
第二题,是我忘记了-1的情况...哎,总是丢三落四的...多谢
作者: Drakedirect    时间: 2007-8-24 03:17
第三题找到一个:25>9^1/2>16^1/4, x>z>y,其实这样的例子还很多,可是考试时一有时间的压力,脑子就想不出来了,多谢yedeanboy提醒

作者: Drakedirect    时间: 2007-8-24 03:23
3. Henry purchased 3 items  during a sale. He received a 20 percent
discount off the regular price of the most expensive item and a 10
percent discount off the regular price of each of the other 2 items.
Was the total amount of the 3 discounts greater than 15 percent of the
sum of the regular prices of the 3 items?
(1) the regular price of the most expensive item was $50, and the regualr price of the next most expensive item was $20.
(2) the regular price of the least expensive item was $15
key: A

题目问是否能确定总折扣大于15%,所以你只要确定折扣最小时能大于15%就可以了
(1)折扣最小时发生在最便宜的物品价格也是20时。总折扣为(20%*50+10%*40)/90=14/90=15.6%
所以(1)可以

(2)仅仅给出最便宜的物品的价格无法确定总折扣。可以举极端的例子。比如3个商品价格一样,则小于15%,最贵的那个商品价格为1000,则必然大于15%

所以选A
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还是有疑问,20不是最便宜的商品阿?所以用20来代替最便宜的商品的出的折扣应该是最大的,所以实际的折扣应该小于15.6%,怎么可能确定与15%的关系呢?

作者: yedeanboy    时间: 2007-8-24 03:27
Drakedirect,你对这道题的理解不对。这道题其实说白了是数学里加权平均的概念。是20%和两个10%的加权平均。权重为商品价格。当10%的折扣的商品,商品价格最大时,可能得到的折扣最低。所以当最便宜的商品价格最高(即20)时,得到的折扣最低。
如果还是不明白,你可以带个极端的数字进去,比如最便宜的商品价格0元,可以得到的折扣肯定高于15.6%

作者: Drakedirect    时间: 2007-8-24 06:09
真是一语点醒梦中人啊!中学的数学全部还给老师了,估计现在能剩下的就只有小学数学了。
多谢yedeanboy
祝你28号旗开得胜,马到成功!

作者: yedeanboy    时间: 2007-8-24 06:36
Drakedirect,大家一起努力,打倒GMAC反动统治!为中国人争光,冲啊~~




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