Math: 51, Verbal: 40
潜水40天，终于可以做一点点贡献了
复习计划
完全借鉴 携隐GMAT小教室 第三期 （http://www.chasedream.com/show.aspx?id=2072&cid=39）， 同时读一些N人心得， 根据个人基础做一些取舍。
数学：考前我很担心， 因为平时总是粗心， 这次发挥不错， 总之是仔细，仔细，再仔细。
语文：考试中和平常作ＧＷＤ的感觉不一样， 觉得难度普遍加大， 特别是阅读， 我的感觉是ＧＭＡＴ实战（包括ＧＭＡＴＰｒｅｐａｒｅ）的文章难度比ＧＷＤ大很多，而且出的题刁钻很多， 不知道大家有没有这种感觉。或许我做ＧＷＤ不够，因为时间关系我只做了ＧＷＤ１－１０．平时做题时间听充裕，考试时时间很紧，最后几道题没看仔细，结果还只剩下十几秒， 建议平时加快速度
ＧＭＡＴＰｒｅｐａｒｅ：虽然重题很多，效果还是不错， 考前模拟７５０，７６０，７７０
不多说了，一点数学ＪＪ：
1. (with figure)
squreroot(3) + squreroot(2)
--------------------------- = ?
squreroot(3) - squreroot(2)
(anw) there is a point in between 9 and 11
2. for savings into bank, for first 0 - 20,000, interest rate is 2 %, next 20,000
to 50,000 interest rate is 2.5%,
and above 50,000 interest is 3.5%, what is the saving amount that the interest equal to 3%?
(anw) 120,000
3. there are two set each with the number 1, 2, 3, 4 ,5, 6. ask randomly choose one number from each set, what is
the probability that the products of the 2 number is divisable by 4
(anw) 12/25, Note: dont forget 4*1, 4*3, 4*5, same I am wrong with this one, the anwer should be (9+6)/36, or my memory is wrong? wait for others to verify the question and anwer
4. DS: ab> ?
1) a-b >0
2) a+b <0
(anw) E,
5. DS: there is a set of number, the mean is m, the standard deviation is R, if add a number x to this set, if r
<= R?
1) x=m
2) m<x<m+R
(anw) D, Note: not sure about 2), made a guess here
6. DS: r, s, t has the same remainder when divided by 5, what is t?
1) r+s=t?
2) 20 <= t <=24
(anw) B, t=20
7. X, Y, Z are points on a line, Y is between X and Z, W is another ponit that WX=WZ, which of the folloing must
be true
(anw) there is many choices, i choose that WX>WY
8. what is the units number of
32,941 * (10^12 - 10^11)/10^13
(anw) the first number (32,941) may not be correct, but the question is similar
9. DS: there is a car and a trunck, in the same duration, car traveled 120 miles, and trunk travelled 100 miles.
what is the average speed of trunk in this period
1) in the first 30 min, car travelled 30 miles
2) the average speed of the car is 10 miles/hour more than the trunk
(anw) B
(anw) B??---Ain't it C?
3. there are two set each with the number 1, 2, 3, 4 ,5, 6. ask randomly choose one number from each set, what is
the probability that the products of the 2 number is divisable by 4
(anw) 13/25???-----ain't it 13/36?
8. what is the units number of
32,941 * (10^12 - 10^11)/10^13
(anw) the first number (32,941) may not be correct, but the question is similar
is the unit number same to the unit number of 9*32941/100?
大家来DISCUSS一下啊~~
还有，恭喜LZ。
和LZ在一个地方，希望沾点喜气~~
我也是!沾沾!
5楼的GG你什么时候考?
分给偶一点
偶的杯子是用来接大小福神的，嘻嘻
big cong
如果我能够考这样的分数我就要笑死了，继续努力复习中
(anw) B??---Ain't it C?这题什么思路?
3. there are two set each with the number 1, 2, 3, 4 ,5, 6. ask randomly choose one number from each set, what is
the probability that the products of the 2 number is divisable by 4
(anw) 13/25???-----ain't it 13/36? 不可以抽相同的嘛?比如2乘以2, 4乘以4. 我怎么是7/18?
8. what is the units number of
32,941 * (10^12 - 10^11)/10^13
(anw) the first number (32,941) may not be correct, but the question is similar
is the unit number same to the unit number of 9*32941/100?
是吧
顺便问下,第四题的r是哪来的? 是敲错了嘛? 应该是什么?
大家来DISCUSS一下啊~~
(anw) B??---Ain't it C?
3. there are two set each with the number 1, 2, 3, 4 ,5, 6. ask randomly choose one number from each set, what is
the probability that the products of the 2 number is divisable by 4
(anw) 13/25???-----ain't it 13/36?
8. what is the units number of
32,941 * (10^12 - 10^11)/10^13
(anw) the first number (32,941) may not be correct, but the question is similar
is the unit number same to the unit number of 9*32941/100?
大家来DISCUSS一下啊~~
嗯，made a mistake in answer of 3, should be 13/36
for 6, 2) alone can identify t=20 as from the question can find that r, s, t all be divisable for 5
for 8, yes, u are right
3. there are two set each with the number 1, 2, 3, 4 ,5, 6. ask randomly choose one number from each set, what is the probability that the products of the 2 number is divisable by 4?
我算出是15/36，数也可以数出来，不知对不对~~~能被4整除的有如下15种取法：
SET1:1 SET2:4 1种取法
SET1:2 SET2:2,4,6 3种取法
SET1:3 SET2:4 1种取法
SET1:4 SET2:123456 6种取法
SET1:5 SET2:4 1种取法
SET1:6 SET2:2,4,6 3种取法
第三题应该是15/36
第六题C，另一个JJ里有讨论过
第九应是D吧，1）实际告诉你car的v=60m/h
谢谢LZ分享：）
lz是否记得一些rcjj呢？
3.
对啊，
楼主再帮忙回忆一些Verbal JJ吧~
嗯，made a mistake in answer of 3, should be 13/36
for 6, 2) alone can identify t=20 as from the question can find that r, s, t all be divisable for 5
for 8, yes, u are right
let's try an example to illustrate: t=20(21), r=15(16), s=10(11) all of them have the same remainder 0(1).
I think we must include (1) to reach the conclusion that T=20
am i rite??
第三题应该是15/36
第六题C，另一个JJ里有讨论过
第九应是D吧，1）实际告诉你car的v=60m/h
同意3和6题。
不过第九题是B，（1）不可以是因为题干中没讲car & truck at constant speed， 所以只是知道一段的速度是不够的。
恭喜楼主！
我真的受到打击了。因为GWD我已经觉得很难了，实战时更难？那不是要我命了！
<= R?
1) x=m
2) m<x<m+R
(anw) D, Note: not sure about 2), made a guess here
这题楼主的答案是对的
1.直接用公式知道是减少的
2.取两个极端，一个是x＝m，另一个是x＝m＋R
得出m<x<m+R也是小的（偶没有算，方法应该对）不保险可以用导数看是否是单调的
所以选D
数学越来越难的说
同意3和6题。
不过第九题是B，（1）不可以是因为题干中没讲car & truck at constant speed， 所以只是知道一段的速度是不够的。
完全同意这个答案
3 15/36
6. C
9 B
(anw) D, Note: not sure about 2), made a guess here
r应该是新数列的 standard deviation，我觉得也是d。
因为standard deviation指的是数列中各数与mean的偏离程度，x的取值如果在m－R<=x<=m+R之间，对standard deviation应该没影响。自己没证过。希望有NN能证一下。
(anw) D, Note: not sure about 2), made a guess here
r应该是新数列的 standard deviation，我觉得也是d。
因为standard deviation指的是数列中各数与mean的偏离程度，x的取值如果在m－R<=x<=m+R之间，对standard deviation应该没影响。自己没证过。希望有NN能证一下。
是有影响的,如果等于m的话肯定是减少的.
设加进去的数是k
n*d`2=(x1-m)`2+(x2-m)`2+....+(xn-m)`2
(n+1)*r`2=(k-m)`2+(x1-m)`2+(x2-m)`2+....+(xn-m)`2
(n+1)*r`2=n*d`2+(k-m)`2
因为m-d<n<m+d 所以(k-m)`2<d`2
r`2<d`2
r<d
我当时是这样推的 就是费点时间
设加进去的数是k
n*d`2=(x1-m)`2+(x2-m)`2+....+(xn-m)`2
(n+1)*r`2=(k-m)`2+(x1-m)`2+(x2-m)`2+....+(xn-m)`2
(n+1)*r`2=n*d`2+(k-m)`2
因为m-d<n<m+d 所以(k-m)`2<d`2
r`2<d`2
r<d
我当时是这样推的 就是费点时间
同意。只要记住结论插入的数x，如果x在m－R<x<m+R之间，standard deviation减小，反之，变大。在m－R和m＋R点不变。
应该是这样的，在m－R<x<m+R内及偏移程度变小，在之外则变大
设加进去的数是k
n*d`2=(x1-m)`2+(x2-m)`2+....+(xn-m)`2
(n+1)*r`2=(k-m)`2+(x1-m)`2+(x2-m)`2+....+(xn-m)`2
(n+1)*r`2=n*d`2+(k-m)`2
因为m-d<n<m+d 所以(k-m)`2<d`2
r`2<d`2
r<d
我当时是这样推的 就是费点时间
同意。只要记住结论插入的数x，如果x在m－R<x<m+R之间，standard deviation减小，反之，变大。在m－R和m＋R点不变。
3题：
两组数字：
1 2 3 4 5 6
1 2 3 4 5 6
从上面按顺序取数与下面的数字相乘，可被4整除的有：1×4，2×2，2×4，2×6，3×4，4×1，4×2，4×3，4×4，4×5，4×6，5×4，6×2，6×4，6×6，其中红色的有重复，略去不算，一共有9种可能。然后从下面的数列中按同样方法取数，也是9种，所以一共为18种，为分子。分母为6×6＝36（或1C6×1C6),得出：18/36=1/2. To be discussed……
第二题确定为120000，是我做错了。
设加进去的数是k
n*d`2=(x1-m)`2+(x2-m)`2+....+(xn-m)`2
(n+1)*r`2=(k-m)`2+(x1-m)`2+(x2-m)`2+....+(xn-m)`2
(n+1)*r`2=n*d`2+(k-m)`2
因为m-d<n<m+d 所以(k-m)`2<d`2
r`2<d`2
r<d
我当时是这样推的 就是费点时间
同意。只要记住结论插入的数x，如果x在m－R<x<m+R之间，standard deviation减小，反之，变大。在m－R和m＋R点不变。
请问如果题目2的条件改为 m-r<x<m 是否仍然选D？ 谢谢
第三题如果可以重复的话,分母是36,分子是9+6, 其中6是1,2,3,4,5,6与4乘的次数, 2*2,2*6,6*6,6*2(如果不能重复就把6*2的一次减去), 所以我算 的是15/36?
对不对?如果错,在哪里?
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