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标题: [求助]GWD-1-26 涛涛 [打印本页]

作者: donald123 时间: 2006-6-8 14:49
标题: [求助]GWD-1-26 涛涛

Q26:

Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce 5/4 w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?

A. 4

B. 6

C. 8

D. 10

E. 12

我想到個比較煩但易明的方法,不知大家怎看?

先找c看,2wx=8,wx=4>wy=2, 不行,因x+y也要3days.

d:wx=5>wy=3,同樣不行,因x+y也要3days

e:wx=6>wy=4,在這題唯一可用答案.

[此贴子已经被作者于2006-6-8 16:17:54编辑过]

作者: hitlzc 时间: 2006-6-8 15:11

你问的题目都是31套中的，是吧？如果是，请在标题中标注下为涛涛版。

设machine x和y的生产速度分别为x、y个widget/day,

根据题干有

w/x-w/y=2

3x+3y=5/4w

求2w/x

令m=w/x,n=w/y

转化为

m-n=2

3/m+3/n=5/4

将m=n+2代入3/m+3/n=5/4经化简得5n^2-14n-24=0,(n-4)(5n+6)=0,得n=4或-6(舍去）

所以m=n+2=6,2m=12

选E

作者: donald123 时间: 2006-6-8 15:52
謝謝

作者: Daoli 时间: 2008-4-8 12:49

THank you! chinese culture -5000

作者: qqqsunny 时间: 2008-5-16 10:49
直接解是最准确的方法，但是很费时间，而且会因为粗心出现错误。
最好用代入法：
由题目知道，x,y一起用3/（5/4）=2.4天
x和y一起用 w/ (wx+wy)= xy/(x+y)
然后由B：2x=8得出x=4,y=2, 代入 xy/(x+y) 不等于2.4
C: 2x=10 得出x=5,y=3,代入 xy/(x+y) 不等于2.4
D: 2x=12; x=6,y=4, 代入xy/x+y 等于 24/10=2.4 正确答案

我算了下时间，大约2分钟可以得出正确答案

[此贴子已经被作者于2008-5-16 11:10:55编辑过]

作者: carriexu 时间: 2008-11-24 23:18
~~

作者: jingle0915 时间: 2010-7-29 19:43
謝謝

作者: 双鱼游 时间: 2010-9-14 17:57
在Manhattan论坛找到的，算起来更简单一点，它是假设x机器完成w件的时间是T

Let T total number of days taken by machine X to produce W widgets.Then Work done by x is 1 day is W/TWork done by machine y in 1 day = W/(T - 2).
Combined work done in 3 days = 3( W/T + W/(t-2) )= 3W( 2T-1 ) / (T- 2) which is equal to 5W/4So equating the two equations we get12( 2T - 1 ) = 5T( T - 2)24T - 12 = 5T2 - 10T5T2 - 32T + 12 = 0(T-6) (5T+2) = 0.
Which gives T = 6.So no. of days to produce 2W widgets = 2T = 12.Ans: E

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