A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling
in the same direction along the same path at a constant rate of 20 miles per hour. The cyclist
stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk
at her constant rate.
How many minutes must the cyclist wait until the hiker catches up?
A 6又2/3
B 15
C 20
D 25
E 26又2/3
对,应该是20,我也忽略了,hiker同时走5分钟了。这么粗心,得满分才怪呢
不怎么会用格式,希望你能看清楚。
(16×5/60 ) ×60
4 =20
16为hiker和cyclist的速度差,5/60是5分钟换算成小时,两数相乘是他们之间的距离差,再除以hiker的速度4miles/hour,为所需的时间,再乘以60换算成minutes。
The cyclist
stops to wait for the hiker 5 minutes after passing her, 关键是此句的理解为pass 后再ride5分钟后wait for the hiker。
不怎么会用格式,希望你能看清楚。
(16×5/60 ) ×60
4 =20
16为hiker和cyclist的速度差,5/60是5分钟换算成小时,两数相乘是他们之间的距离差,再除以hiker的速度4miles/hour,为所需的时间,再乘以60换算成minutes。
The cyclist
stops to wait for the hiker 5 minutes after passing her, 关键是此句的理解为pass 后再ride5分钟后wait for the hiker。
支持!
此题容易误选D.容易忽略5分钟hiker和cycilist都在行进。
stops to wait for the hiker 5 minutes after passing her, 关键是此句的理解为pass 后再ride5分钟后wait for the hiker。
我做题的时候就在这绕住了,怎么想怎么不对。
明白了,多谢!
欢迎光临 ChaseDream (https://forum.chasedream.com/) | Powered by Discuz! X3.3 |