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标题: GMAT-6-22请教求解思路 [打印本页]

作者: sv2000 时间: 2005-11-11 13:53
标题: GMAT-6-22请教求解思路

The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

The argument above is flawed because it fails to take into account

changes in the population density of both Parkdale and Meadowbrook over the past four years

how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale

the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale

the violent crime rates in Meadowbrook and Parkdale four years ago

how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures

作者: yangsh 时间: 2005-11-11 14:27

做个乘法。

作者: deanjiang 时间: 2005-11-11 22:05

选D

只有知道4年前的各自暴力犯罪率，才能知道上升各自的百分比后，今年的犯罪率。

欢迎讨论

作者: lyle 时间: 2005-11-11 22:43

同意C。

问的是哪一个more likely，所以用比率。

作者: sv2000 时间: 2005-11-12 10:52

明白了，谢谢。支持Deanjiang的解释，选D.

[此贴子已经被作者于2005-11-12 10:52:57编辑过]

作者: steveyangxt 时间: 2005-12-17 20:36

原来1% 增加60% 现在是 1。6%

原来40%增加10%现在是44%

作者: yangxiaogang 时间: 2005-12-18 00:53

D is the best

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