28-7: In 1960’s studies of rats, scientists found that crowding increases the number of attacks among the animals significantly. But in recent experiments in which Rhesus monkeys were placed in crowded conditions, although there was an increase in instances of “coping” behavior – such as submissive gestures and avoidance of dominant individuals – attacks did not become any more frequent. Therefore it is not likely that, for any species of monkey, crowding increases aggression as significantly as was seen in rats.
Which of the following, if true, most strengthens the argument?
A: All the observed forms of coping behavior can be found among rhesus monkeys living in uncrowded conditions.
B: In the studies of rats, nondominant individuals were found to increasingly avoid dominant individuals when the animals were in crowded conditions.
C: Rhesus monkeys respond with aggression to a wider range of stimuli than any other monkeys do.
D: Some individual monkeys in the experiment were involved in significantly more attacks than the other monkeys were.
E: Some of the coping behavior displayed by rhesus monkeys is similar to behavior rhesus monkeys use to bring to an end an attack that has begun.
题干的意思是说，所有种类的猴子，不会像老鼠一样，挤在一起就打，并不太可能。
C的意思：Rhesus比起任何其他的猴子，因为更多的因素，而导致打斗行为。
E的意思：在实验中Rhesus表现出一种使打斗结束的行为。
那么，明显E要比C make sense。C其实比较的猴子之间，而与crowding这个前提无关。
我觉得E更好！
请大家给点意见
help pls!
我也觉得是选e,c看上去像无关
已经确认，是E
已经确认，是E
楼上在偷换概念。
不是说attack增加，而是使attack减少的动作增加。
consider this scenario, 我和一堆人挤在一起，我们不但没有打架，还老是互相说，不要打了，不要打了。
那么对于我们这组人来说，挤在一起，不见得一定要扁成一团。
对的 是这么回事。
支持C. ANY太唐突了, 作为结论中的新概念, 应该要有说明或者与前文有逻辑联系. C很好的填补了这个GAP.
E应该是无关项.
I MEAN the exactly one!~
3ks
答案就是C啦。
文中测试了一种猴子，发现它不会因为特拥挤而怒了，因此下了一个结论：for any species of monkey，都不会因为拥挤而怒了。
问题问，如何支持这个结论?
E说（我就意义啦，呵呵）测试用的猴子（相比其他猴子）比较敏感，对很多很多刺激都会作出发怒的反映。
因此呢，支持。也就是说：这么易怒的猴子都不因为拥挤而发怒，更何况那些（温文尔雅的，我意义的，呵呵）猴子呢？
顶！
同问，我也选A
ding
但是it is not likely再加个any的意思是说只要有一种猴子满足“拥挤条件下不象老鼠一样激进”就行了啊，并不需要所有猴子都不激进啊
我觉得选A是对的：
文中只说有cope行为上升，所以只要否认这种行为是激进行为就行了，只要这个行为在不拥挤的情况下也发生，就说明它不是激进行为
orignally i choose A also. because i thought the coping behavior is mentioned in the passage, therefore, the answer must be related to it. however, after readingthe explaination of C, i realized that choice A is just one to make us confused.
because, A cannot prove that Rhesus monkeys r not like rats, although it SEEMS like, and SEEMS related to the questions.
Even all the moneys have coping behaviors, so ? its not related to crowded environment or aggression.
personal opinion. welcome ur correction.
就是C，E是削弱
c: 能使Rm打架的因素比其他猴子多，说明Rm比其他猴子更容易打架，连Rm都表现出不怎么打架，其他猴子就更不会了。
E：就是由于在实验中所看到的行为是打架结束的象征，所以说明在看到实验结果前猴子就已经打过架了。当然削弱了
Situation：Rats： 拥挤
è
明显增加打架次数
Rhesus monkey：拥挤
è
躲避行为
＋
打架次数没有增加
结论：任何种类的猴子都不会像老鼠，对拥挤反应出恼怒。
从Rhesus monkey 推到任何猴子，从打架次数推到aggression。选项就要支持这两个桥。
感觉有点弱支持。A的意思应该是想说躲避行为不是aggression的一种表现，一个排他因。但是这点原文似乎已经说了（注意although引导让步状语从句，强调重点在后半句，所以原文病没有把coping behavior算成是像打架那样的aggressive behavior）。
increases the number of attacks among the animals significantly.”和倒数第二句说Rhesus monkey的“attacks did not
become any more frequent”所以这个属于无关项。
楼上说得很明白，感谢
A不是弱支持，而是无关：
猴子在常态下也会表现那些在拥挤时所表现的动作，能证明什么？证明那些动作也是众多的常态动作之一？即便证明了这一点也说明不了什么。C是最佳，前面已经有人分析过了。连最敏感的猴子都不发怒，那么any other也不会
Premises: Experiment on Rhesus monkeys; Result no more aggression
Conclusion: it is not likely that, for any species of monkey, crowding increases aggression as significantly as was seen in rats.
The conclusion is intends to generalize the experiment finding from a single group Rhesus to all other groups of monkeys.
C: is the only choice has mentioned some form of comparison between two.
Rhesus monkeys respond with aggression to a wider range of stimuli than any other monkeys do.
Reaction to a wider range of stimuli is an reasonable factor in considering the monkey’s level of comparison. I tells that Rhesus monkey less aggressive not due to there are insensitive to wide range of stimuli, instead they are just as sensitive as the other groups.
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