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标题: 求助OG19CR633题 [打印本页]

作者: lin9 时间: 2018-9-10 19:32
标题: 求助OG19CR633题
看样子是道老题了，可是没看到有人问A选项，po出来求助大家

Debater: The average amount of overtime per month worked by an employee in the manuf[color=rgb(251, 77, 0) !important]acturing division of the Haglut Corporation is 14 hours. Most employees of the Haglut Corporation work in the manufacturing division. Furthermore, the average amount of overtime per month worked by any employee in the company generally does not fluctuate much from month to month. Therefore, each month, most employees of the Haglut Corporation almost certainly work at least some overtime.

The debater’s argument is most vulnerable to criticism on which of these grounds?

(A) It takes for granted that the manufacturing division is a typical division of the corporation with regard to the average amount of overtime its employees work each month.

(B) It takes for granted that if a certain average amount of overtime is worked each month by each employee of the Haglut Corporation, then approximately the same amount of overtime must be worked each month by each employee of the manufacturing division.

(C) It confuses a claim from which the argument’s conclusion about the Haglut Corporation would necessarily follow with a claim that would follow from the argument’s conclusion only with a high degree of probability.

(D) It overlooks the possibility that even if, on average, a certain amount of overtime is worked by the members of some group, many members of that group may work no overtime at all.

(E) It overlooks the possibility that even if most employees of the corporation work some overtime each month, any one corporate employee may, in some months, work no overtime.

请问大家为什么A选项不能理解成：加班时间基本固定，大部分员工都在制造部，制造部的人要加班，（制造部是典型的部门），至少大部分人都要加班

削弱也就是说，只有制造部要加班，其他部门不一定要加班。把制造部当成典型的部门来看，所以这样不对。

求助大家，谢谢Thanks♪(･ω･)ﾉ！

作者: L.M. 时间: 2018-9-10 21:12
我觉得A选项翻译过来意思应该是：“它忽略了这个事情：考虑到部门中员工的每月的超时时间，MD是公司内很有代表性的部门。”

也就是说MD部门的情况在整个公司都存在。那这样的话，不管员工在哪个部门都没有区别都是加班，反而strengthen了结论（大部分员工都加班）。

作者: kluivert 时间: 2018-9-10 23:11
结论是most most most employees

无论MD是否典型都无关 ..

不典型，那就参照MD就可以了，完全有可能是只有一些员工加班（低于总员工数的一半）

典型，也同样的道理，每个部门都是低于一半数量的人会加班，那结果还是并不是大部分人都加班

数字化一下

1000员工
800 MD
200 其他

MD 有200人会加班 ( 整个部门的25% )

不典型，那md还是只有200人，其他部门的就相对少。。总加班人数还是低于25% ，远低于most(一半以上）

典型，就是有普遍性那就是整个公司都25% = 250

Md有200，加上其他部门 50 。。。还是远低于most

所以A真的不能用了加强或削弱
是不是我对于这个typical理解反了..不过都不会影响结果

作者: L.M. 时间: 2018-9-11 12:47

kluivert 发表于 2018-9-10 23:11
结论是most most most employees

无论MD是否典型都无关 ..

柯林斯里面对typical的解释是：

You use typical to describe someone or something that shows the most usual characteristics of a particular type of person or thing, and is therefore a good example of that type.

也就是具有普遍性的意思。

作者: kluivert 时间: 2018-9-11 12:54

L.M. 发表于 2018-9-11 12:47
柯林斯里面对typical的解释是：

You use typical to describe someone or something that shows the mos ...

哈哈谢谢

现在脑袋越来越大了

OG还没碰..瞎在gmatclub看题.. 发现CR好多好偏的题目完全没价值貌似很多题是法学院的逻辑考试

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