Q27:
Of the cans of peaches inspected yesterday at a certain plant, 1.5 percent failed to pass inspection. Of the cans that failed inspection,
(1) 450 of the cans of peaches inspected yesterday at the plant failed to pass inspection.
(2) 29,550 of the cans of peaches inspected yesterday at the plant passed inspection.
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
哪位老大帮忙翻译并解答一下，讨论链接中没有讨论过这道题。晕啊。
检查一批罐头。1.5%不合格。在所有不合格的罐头里面，有5/6是贴错标签的，剩下的是罐子凹陷进去的。如果贴错标签或者凹罐都算不合格，问昨天有多少凹罐？
(1) 昨天有450个不合格的。所以有1/6是凹罐的就是75罐，可以
(2)检查了29,500个罐头。29500*1.5%*1/6，也可以
D？？
我觉得此题有争议, 因为题中 "If all of the cans that were incorrectly labeled or dented failed inspection" 只能说明所有贴错标签的和凹陷的罐头都没通过质检, 但是不能说明所有没通过质检的罐头只是贴错标签的和凹陷的两种罐头. 应该还可以包括其他的. 举个例子说: 全校所有的单亲孩子都在我们班, 能说明我们班就只有单亲孩子没有别的孩子吗? 所以我觉得应该选E
检查一批罐头。1.5%不合格。在所有不合格的罐头里面，有5/6是贴错标签的，剩下的是罐子凹陷进去的。如果贴错标签或者凹罐都算不合格，问昨天有多少凹罐？
(1) 昨天有450个不合格的。所以有1/6是凹罐的就是75罐，可以
(2)检查了29,500个罐头。29500*1.5%*1/6，也可以
D？？
Agree with LS on the answer, but not the calculation on (2).
Basically, the question is: can we find the TOTAL numbers of cans inspected.
1) 450/(1.5%)=30,000; so there are a total of 30,000 cans; then find the number of dented (30,000*1.5%*1/6)
2) 29,500=(1-1.5%)=30,000; same as statement one.
Two statements are telling us the same thing. So D.
Hope it's correct.
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