ChaseDream

标题: LSAT--1--4--19 [打印本页]

作者: 飞06    时间: 2005-3-20 15:17
标题: LSAT--1--4--19

19. There are at least three people in the room. At most two people in the room recognize each other. At least one person in the room recognizes everybody else in the room.


Which one of the following is NOT consistent with the above?


(A) Four people are in the room


(B) No two people in the room recognize each other.


(C) At most one person in the room recognizes everybody else in the room.


(D) Anyone in the room who recognizes any other person in the room is also recognized by that person..


(E) Two people in the room recognize every one else in the room.



答案是D,不懂得


谁分析分析?谢谢


作者: 飞06    时间: 2005-3-20 16:00

已经讨论出结果了

本题题眼在于“NOT consistent with ”

所以只要判断哪个绝对不可能就好了,结果是除D外,其他都是可以由题目中假设推出来的,惟独D不行,故选D,完毕。欢迎补充。






欢迎光临 ChaseDream (https://forum.chasedream.com/) Powered by Discuz! X3.3