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[求助]GWD-1-26 涛涛

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楼主
发表于 2010-9-14 17:57:05 | 显示全部楼层
在Manhattan论坛找到的,算起来更简单一点,它是假设x机器完成w件的时间是T

Let T total number of days taken by machine X to produce W widgets.Then Work done by x is 1 day is W/TWork done by machine y in 1 day = W/(T - 2).
Combined work done in 3 days = 3( W/T + W/(t-2) )= 3W( 2T-1 ) / (T- 2) which is equal to 5W/4So equating the two equations we get12( 2T - 1 ) = 5T( T - 2)24T - 12 = 5T2 - 10T5T2 - 32T + 12 = 0(T-6) (5T+2) = 0.
Which gives T = 6.So no. of days to produce 2W widgets = 2T = 12.Ans: E
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