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TT31-1,居然错了28题,大家别笑,快来教教我吧.

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楼主
发表于 2007-5-19 11:59:00 | 只看该作者

TT31-1,居然错了28题,大家别笑,快来教教我吧.

Q2:

A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster.  If a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?

 

A.        0

B.        1/9

C.        2/9

D.       1/3

E.        1

Answer:

首先,你要知道这道题的答案需要把每一辆车被选择一次的概率相乘.那么第一辆车可任选即概率为1,第二次在三辆车中选另两辆未被选过的车中的一辆的概率为2/3,最后一次在三辆车中选唯一一辆未被选过的车的概率为1/3: 1*2/3*1/3=2/9

这题是搜索到NN的解释,看不懂?请再明示一下吧.

Q5:

Is x > k?

(1)
                
  2x • 2k = 4

(2)
                
  9x • 3k = 81

                  

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.

答案是E,我觉得是C,主要是我数学太差了,所以提上来再问问大家.

Q9:

A gardener is going to plant 2 red rosebushes and 2 white rosebushes.  If the gardener is to select each of the bushes at random, one at a time, and plant them in a row, what is the probability that the 2 rosebushes in the middle of the row will be the red rosebushes?

 

A.      1/12

B.      1/6

C.      1/5

D.     1/3

E.      1/2

to Q9.

4 rosebushes, so the total possibility is Permutation(4,4), ie, there are 24 possible outcomes to order the place of them,

then for the red rosebushes in the middle, there are two outcomes as r1 r2 or r2 r1 in the middel of the place, and for the white ones, there are two outcomes as well, ie, w1 r r w2, w2 r r w1 , so the numerator should be 2*2, and denominator should be 24. 4/24=1/6

看了解释,更不明白了.请问有更合适我这种程度的做法吗?

11.In a corporation, 50 percent of the male employees and 40 percent of the female employees are at least 35 years old.  If 42 percent of all the employees are at least 35 years old, what fraction of the employees in the corporation are females?

 A.      3/5 B.      2/3  C.      3/4   D.     4/5   E.      5/6

我的做法是设总员工为100人, 那么女员工占总人数的比例是:40/100=2/5,答案是D,不知道怎么算了.

我的做法是设总员工为100人, 那么女员工占总人数的比例是:40/100=2/5,答案是D,不知道怎么算了.

Q14:

If 1050 – 74 is written as an integer in base 10 notation(10为底数), what is the sum of the digits in that integer?

 

A.      424

B.      433

C.      440

D.     449

E.      467

10^50=10000000....00000(500)

10^50-74=9999999...99926(50-29)

所以sum=48*9+2+6=440

(x+5+2x)^2 - (x+5)^2 = 132   => x=3, 这是某一题的解题步骤,我把它分解成8X^2+20X-132=0,就怎么也算不下去了, 132的因子好像没有相加等于20的呀.

Q20: If x > 0, then 1/[√(2x)+√x] =

 

A.      1/√(3x)

B.      1/[2√(2x)]

C.      1/(x√2)

D.     (√2-1)/√x

E.      (1+√2)/√x

(2x)-x/((2x)+x)((2x)-x)

((2x)-x)/x

分式上下同除√x),得   (2-1)/x

(2x)-x/((2x)+x)((2x)-x)---(2x)-x/X,但怎么也求不出等于(2-1)/x. 不知道哪步出错了!!~~??

Q22:

In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term.  What is the sum of the 16th, 17th, and 18th terms in the sequence?

 

A.      218

B.      3(217)

C.      7(216)

D.     3(216)

E.      7(215)

没有搜索到讨论,不知道怎么思路??

Q23:

In the xy-plane, point (r, s) lies on a circle with center at the origin.  What is the value of r2 + s2?

(1)
                                
  The circle has radius 2.

(2)
                                
  The point (√2, -√2) lies on the circle.

                  

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.

也是没有思路,更没有搜索到讨论贴??!!

Q25:

A photographer
                                
will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row.  The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her.  How many such arrangements of the 6 people are possible?

 

A.      5

B.      6

C.      9

D.     24

E.      36

我搜索到的讨论都是土算算出来的,我可土算只能算出4种排列.请教有啥科学算法不?

Q28:

For any positive integer n, the sum of the first n positive integers equals [n(n+1)]/2.  What is the sum of all the even integers between 99 and 301?

 

A.      10,100

B.      20,200

C.      22,650

D.     40,200

E.      45,150

(((301-99/2*301+99))/2=20200

如果按以上算法(我搜索来的), 题目中的条件[n(n+1)]/2还有什么用呢? 而且这个算法俺想不明白思路.

31.A positive integer n is said to be “prime-saturated” if the product of all the different positive prime factors of n is less than the square root of n.  What is the greatest two-digit prime-saturated integer?

 

A.      99

B.      98

C.      97

D.     96

E.      95

这题是指:5个答案中哪个数的所有质因子之积小于这个数的平方根? 我是把答案带入算的, 还有科学方法不?

Q34:

The function f is defined by f(x) = - 1/x for all nonzero numbers x.  If f(a) = - 1/2 and f(ab) = 1/6, then b =

 

A.      3

B.      1/3

C.      - 1/3

D.     -3

E.      –12

答案是:1/3; 可我指的是-3, 这是怎么算出1/3的呢?

Q36:

Each signal that a certain ship can make is comprised of 3 different flags hanging vertically in a particular order.  How many unique signals can be made by using 4 different flags?

 

A.      10

B.      12

C.      20

D.     24

E.      36

要考虑不同的排列顺序,所以是A(3,4)=24----不理解这位NN的解释?

Q37:

A jar contains 16 marbles, of which 4 are red, 3 are blue, and the rest are yellow.  If 2 marbles are to be selected at random from the jar, one at a time without being replaced, what is the probability that the first marble selected will be red and the second marble selected will be blue?

 

A.      3/64

B.      1/20

C.      1/16

D.     1/12

E.      1/8

2次取,2次的概率相乘。第一次从16中取一个红的:C(4,1)/C(16,1),第二次从15中取一个蓝的:C(3,1)/C(15,1)

 我不懂为什么要用红)---4个里取1个除以16里取1呢? 就是除法在概率题里用在什么情况下呢?

我的问题太多了, 身边人都懒得教我(嘻嘻,都是牛人F1们,我的数学题对他们来说太易了),我是实在不好意思了,老来麻烦大家. 我的OG看完概念了,在补充看陈向东,可一遇到实题就傻了.笨笨笨的乌,可我也想飞....

再次感谢大家!!!

沙发
发表于 2007-5-19 14:16:00 | 只看该作者

Q2:

there are 3*2*1=6 different ways to enter 3 different cars in three times, while there are 3*3*3=27 ways to enter 3 cars no matter different or not in three times. Thus, the answer should be 6/27=2/9.

Q5:

Is it the question intact? Where is the definition of x and k? If there is no specific definition of x and k, the answer should surely be E because there is too much uncertainty.

板凳
发表于 2007-5-19 23:38:00 | 只看该作者

Q5,我觉得是C。联立方程x+k=2 2x+k=4可以得出具体的x, k值,跟x,k为整数或者其它没有关系啊

 

Q9,4个排一排,要求中间2个是红色。把四个看成不同元素,排列概率是P(4,4)=24,中间两个为红色的排列概率为C(1,2)*C(1,2)=4,所以为1/6; 从组合的观点来看,只有红白两种选择,4个中任选2个的概率为C(2,4),中间两个为红色的组合只有一种,也为1/6

 

Q11,题目理解有误,是女员工中的42%>=35 years old。设M、F为分别男女员工数目,0.5M+0.4F=0.42*(M+F),可得D

 

Q14, 8X^2+20X-132=0 => 2X^2+5X-33=0 =>(2X+11)(X-3)=0

 

Q20, [(2x)-x]/X => 分子分母同时除以x 不就是答案吗?

 

Q22, 该数列为: 2^0, 2^1, 2^2......2^n   第16、17、18分别为2^15, 2^16, 2^17, 相加选E

 

Q23, 圆心位于直角坐标系原点, 半径为M的圆的方程为: r^2+ s^2=M^2, 其中(r,s)是圆周上的点。所以选D

 

Q25,我觉得用土法直接排比较好啊,因为限制条件太多。具体排列为:654|321, 653|421, 652|431,  642|531, 643|521

 

Q28,[n(n+1)]/2 是等差数列求和公式,解答的思路也是用等差数列求和公式直接计算

 

Q31,我也觉得直接验证答案比较快

 

Q34, 我也算出是-3,

Q36,4个中选出3个排列,C(3,4)*P(3,3)= 24

Q37, 第一次取的概率为4/16, 因为不放回,第二次取的概率为3/15, 两次相乘得1/20

地板
 楼主| 发表于 2007-5-20 10:23:00 | 只看该作者
以下是引用清如水在2007-5-19 14:16:00的发言:

Q2:

there are 3*2*1=6 different ways to enter 3 different cars in three times, while there are 3*3*3=27 ways to enter 3 cars no matter different or not in three times. Thus, the answer should be 6/27=2/9.

Q5:

Is it the question intact? Where is the definition of x and k? If there is no specific definition of x and k, the answer should surely be E because there is too much uncertainty.

谢谢如水MM,你的第2题解答,我看懂了,确实是一题解法可以多样,你的思路我能明白了.呵呵.
5#
 楼主| 发表于 2007-5-20 11:53:00 | 只看该作者

谢谢大鸟!居然都教我了,嘻嘻,太不好意思了.

有一点小问题:

14题的 8X^2+20X-132=0 => 2X^2+5X-33=0 =>(2X+11)(X-3)=0,11,-3相乘等于-33,可相加不等于5呀?是不是X^2+5X-33=0就肯定要求它们相加也得等于5了呢?

这是漏看的, 牛牛还能再教教我呢?我不会的是, 1050 – 74 , 如何将74化为以10为底数的形式呢?

If 1050 – 74 is written as an integer in base 10 notation(10为底数), what is the sum of the digits in that integer?

 

A.      424

B.      433

C.      440

D.     449

E.      467

10^50=10000000....00000(500)

10^50-74=9999999...99926(50-29)

所以sum=48*9+2+6=440

Q22, 该数列为: 2^0, 2^1, 2^2......2^n   第16、17、18分别为2^15, 2^16, 2^17, 相加选E, 我就是不晓得如何相加2^15, 2^16, 2^17,呵呵.

Q28,[n(n+1)]/2 是等差数列求和公式,解答的思路也是用等差数列求和公式直接计算, 这里的等差数列求和公式我查了书,有3个公式,觉得都算不出来,不知道你用的是哪种?

关于排列组合题9和36的疑惑

Q9,4个排一排,要求中间2个是红色。把四个看成不同元素,排列概率是P(4,4)=24,中间两个为红色的排列概率为C(1,2)*C(1,2)=4,所以为1/6; 从组合的观点来看,只有红白两种选择,4个中任选2个的概率为C(2,4),中间两个为红色的组合只有一种,也为1/6

Q36,4个中选出3个排列,C(3,4)*P(3,3)= 24

为什么第9题是组合/排列; 而36题是组合*排列? 

再次感谢火鸟

6#
发表于 2007-5-20 21:51:00 | 只看该作者
以下是引用maomm在2007-5-20 11:53:00的发言:

谢谢大鸟!居然都教我了,嘻嘻,太不好意思了.

有一点小问题:

14题的 8X^2+20X-132=0 => 2X^2+5X-33=0 =>(2X+11)(X-3)=0,11,-3相乘等于-33,可相加不等于5呀?是不是X^2+5X-33=0就肯定要求它们相加也得等于5了呢? 注意系数

这是漏看的, 牛牛还能再教教我呢?我不会的是, 1050 – 74 , 如何将74化为以10为底数的形式呢? 原题是说某个数用科学计数法表示为1050 – 74 ,并不是要将74化为以10为底数的形式

If 1050 – 74 is written as an integer in base 10 notation(10为底数), what is the sum of the digits in that integer?

 

A.      424

B.      433

C.      440

D.     449

E.      467

10^50=10000000....00000(500)

10^50-74=9999999...99926(50-29)

所以sum=48*9+2+6=440

Q22, 该数列为: 2^0, 2^1, 2^2......2^n   第16、17、18分别为2^15, 2^16, 2^17, 相加选E, 我就是不晓得如何相加2^15, 2^16, 2^17,呵呵.土法15个2相乘

Q28,[n(n+1)]/2 是等差数列求和公式,解答的思路也是用等差数列求和公式直接计算, 这里的等差数列求和公式我查了书,有3个公式,觉得都算不出来,不知道你用的是哪种?项数*(首项+尾项)/2

关于排列组合题9和36的疑惑

Q9,4个排一排,要求中间2个是红色。把四个看成不同元素,排列概率是P(4,4)=24,中间两个为红色的排列概率为C(1,2)*C(1,2)=4,所以为1/6; 从组合的观点来看,只有红白两种选择,4个中任选2个的概率为C(2,4),中间两个为红色的组合只有一种,也为1/6

Q36,4个中选出3个排列,C(3,4)*P(3,3)= 24

为什么第9题是组合/排列; 而36题是组合*排列? 这个没有一定之规,还是看看概率论比较好,

再次感谢火鸟

7#
 楼主| 发表于 2007-5-21 02:38:00 | 只看该作者
谢谢火鸟的耐心解答.
8#
发表于 2017-2-4 21:35:26 | 只看该作者
ddddddddd
9#
发表于 2017-2-6 10:47:31 | 只看该作者
弱问 TT31-1是什么资料,CD上有下吗?
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