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请教PREP数学

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楼主
发表于 2011-6-23 22:40:56 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
n, y are positive integers and 450y=n^3, which of the following must be an integer?
I. y/(3*2^2*5)
II. y/(3^2*2*5)
III. y/(3*2*5^2)


A. None
B. I only
C. II only
D. III only
E. I, II, III




求教啊。450=5^2*3^2*2
按理来说应该是II和III都对啊。。。先深深感谢各位大侠的帮助!
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沙发
发表于 2011-6-23 22:47:55 | 只看该作者
450y=n^3

2*(5^2)*(3^2)*y = n^3

n = a*2*5*3

y= b*(2^2)*3*5

Only I has to be an integer.
板凳
 楼主| 发表于 2011-6-23 23:46:04 | 只看该作者
Hey, I understand that you can get2*(5^2)*(3^2)*y = n^3

but how did the following you get from the last step?
n = a*2*5*3



Also, from this step how did you get y= b×2^2×3×5
why 2^2??


Thanks!!

地板
发表于 2011-6-24 00:11:14 | 只看该作者
If 2 is a factor of n^3, then 2 must be a factor of n.  
If 3 is a factor of n^3, then 3 must be a factor of n.
If 5 is a factor of n^3, then 5 must be a factor of n.
So n = a*2*3*5

Then 450y=n^3 = (a*2*3*5)^3; y=a^3*2^2×3×5 = b*2^2×3×5
5#
 楼主| 发表于 2011-6-24 02:06:00 | 只看该作者
拜谢大侠
6#
发表于 2011-8-2 14:47:43 | 只看该作者
厉害厉害!!遇到这种题,是不是从答案给的因子出发去凑呀?
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